Answer:
Explanation:
First of all, we need to calculate the magnetic field magnitude at 25 cm from the wire, which is given by
where
μ0 = 4π × 10-7 t · m/a is the vacuum permeability
I = 12 A is the current in the wire
r = 25 cm = 0.25 m is the distance from the wire
Substituting,
Now we can calculate the energy density of the magnetic field, which is given by
And substituting, we find
Answer:
A:- 50 J
B:- 500 J
Explanation:
a) Given that a 25 N force is applied to move the box. Also the floor is having friction surface.
So in order to move the box, the floor should have friction of atleast 25 N.
∴ friction = 25 N
Work done = force * displacement of box
Given, the box is moved 2 m across the floor
So, Work done = friction * 2 m
= 25 * 2
= 50 J
b) Given, the box is having weight of 250 N weight
Gravitational force is acting on the box which is equal to (mass * gravity)
∴ Force = 250 N
The box is lifted 2 m above the floor.
So, displacement = 2 m
Work done = force * displacement of box
Work done = 250 * 2
= 500 J
Answer:
The distance that the racecar traveled is indeed 500m. But at the end of the lap, it is right back where it started. So overall, it has been displaced 0m.
Explanation: