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Ket [755]
3 years ago
13

A lab team places 0.250g of an unknown solid acid in an Erlenmeyer flask. They neutralize the solid acid with 15.0ml of 0.210 M

Na(OH)(aq). One mole of the acid reacts with one mole of the base. Calculate the molar mass of the unknown solid acid O 158 g/mol 0 7.9 g/mol 79.4 g/mol 0 763 g/mol​
Chemistry
1 answer:
Otrada [13]3 years ago
6 0

Answer:

<u>Molar</u><u> </u><u>mass</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>unknown</u><u> </u><u>acid</u><u> </u><u>is</u><u> </u><u>7</u><u>9</u><u> </u><u>grams</u>

Explanation:

We have to first get moles in 15.0 ml of sodium hydroxide solution:

{ \sf{1 \: l \: of \:NaOH \: contains \: 0.210 \: moles }} \\ { \sf{0.015 \: l \: of \: NaOH \: contain \: (0.015 \times 0.210) \: moles }} \\  { \underline{ = 0.00315 \: moles \: of \: NaOH}}

since mole ratio of acid : base is 1 : 1, so;

moles of acid that reacted is <u>0</u><u>.</u><u>0</u><u>0</u><u>3</u><u>1</u><u>5</u><u> </u><u>m</u><u>o</u><u>l</u><u>e</u><u>s</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>u</u><u>n</u><u>k</u><u>n</u><u>o</u><u>w</u><u>n</u><u> </u><u>a</u><u>c</u><u>i</u><u>d</u><u>.</u>

then we've to get molar mass:

{ \sf{0.00315 \: moles \: of \: acid \: weigh \: 0.250 \: g}} \\ { \sf{1 \: mole \: of \: acid \: weighs \: ( \frac{1 \times 0.250}{0.00315} ) \: g}} \\ { \underline{ = 79.4 \: g \approx79 \: grams}}

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