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sertanlavr [38]
3 years ago
7

3. Look at the positions of calcium, beryllium, and magnesium on the periodic table. Based on their locations, predict how many

valence electrons these elements have and predict what the reactivity of these elements will generally be.
Chemistry
2 answers:
Nitella [24]3 years ago
7 0
Ca= 2 ve
Be=2 ve
Mg=2 ve because they are in Group 2a.
 They are slightly less reactive than Group 1a, but more dense that Group 1a.
TEA [102]3 years ago
6 0

Explanation:

It is known that beryllium, calcium and magnesium are all group 2 elements.

Atomic number of Be is 4, magnesium has 12 and calcium has atomic number 20.

So, they contain 2 valence electrons and in order to attain stability they readily lose their valence electrons.

As a result, they tend to form an ion with +2 charge.

Since, it is easy to lose two electrons to attain stability hence, elements of group 2 are very reactive in nature.

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What is the kinetic energy of a 10 kg object that has a velocity of 1.5 m/s
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Lead (ll) nitride+ammonium sulfate > lead(ll) sulfate + ammonium nitride
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Answer:

Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N

Explanation:

Let's rewrite the given word equation in its chemical balanced equation representation:

1. Lead(II) nitride is represented by lead, Pb, in an oxidation state of 2+, while nitride is a typical nitrogen anion with a state 3-. As a result, the lowest common multiple between 2 and 3 is 6, meaning 2 lead cations are needed to balance 3 nitrogen anions: Pb_3N_2.

2. Ammonium sulfate consists of an ammonium cation with a 1+ charge and sulfate anion with a 2- charge, two ammonium cations needed: (NH_4)_2SO_4.

3. Lead(II) sulfate would have one lead cation and one sulfate anion, as they have the same magnitude of charges with opposite signs: PbSO_4.

4. Ammonium nitride would require three amonium cations to balance the nitride anion: (NH_4)_3N.

Let's write the balanced equation:

Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N

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4 years ago
What mass of sucrose (C12H22O11) should be combined with 546 g of water to make a solution with an osmotic pressure of 8.80 atm
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<u>Answer:</u> The mass of sucrose required is 69.08 g

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = 8.80 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (sucrose) = ?

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 564 mL    (Density of water = 1 g/mL)

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

T = Temperature of the solution = 290 K

Putting values in above equation, we get:

8.80atm=1\times \frac{\text{Mass of sucrose}\times 1000}{342.3\times 546}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 290K\\\\\text{Mass of sucrose}=\frac{8.80\times 342.3\times 546}{1\times 1000\times 0.0821\times 290}=69.08g

Hence, the mass of sucrose required is 69.08 g

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