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storchak [24]
3 years ago
8

How many atoms are in c6h4c12

Chemistry
1 answer:
Mekhanik [1.2K]3 years ago
6 0

Answer:

their are a it is in the chemicle

Explanation:18 carbon and 4 hydrogen

so it is a toatle of 22 atoms

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A certain orbital of the hydrogen atom has n = 4 and l = 2 what are the possible values of ml for this orbital?
Nadya [2.5K]

The ml is also called as the magnetic quantum number. The value of ml can range from –l to +l including zero. Hence all of the possible values for ml given that l = 2 are:

<span>-2, -1, 0, + 1, + 2</span>

3 0
3 years ago
What is the name for a substance that cannot be separated into simpler substances ?
Delicious77 [7]

Answer:a element

Explanation:

4 0
3 years ago
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Using your knowledge of colligative properties explain whether sodium chloride or calcium chloride would be a more effective sub
Lisa [10]
Sodium chloride because it contains the most reactive metal(sodium) and most reactive non-metal(chlorine).
6 0
3 years ago
A sample of 0.281 gg of an unknown monoprotic acid was dissolved in 25.0 mLmL of water and titrated with 0.0950 M NaOH NaOH. The
tensa zangetsu [6.8K]

Answer:

98.6 g/mol.

Explanation:

Equation of the reaction

HX + NaOH--> NaX + H2O

Number of moles = molar concentration × volume

= 0.095 × 0.03

= 0.00285 moles

By stoichiometry, 1 mole of HX reacted with 1 mole of NaOH. Therefore, number of moles of HX = 0.00285 moles.

Molar mass = mass ÷ number of moles

= 0.281 ÷ 0.00285

= 98.6 g/mol.

5 0
3 years ago
HELP PLSSSSS!!
11Alexandr11 [23.1K]

Answer:

68133080.02 g

Explanation:

I believe that the question is to find the mass of air in the room and not the molar mass of air since the molar mass of air was already given in the question as 28.97 g/mol.

Now, if 1 mole of a gas occupies 22.4 L

x moles of air occupies 52,681,428.8 Liters

x = 1 * 52,681,428.8 /22.4

x = 2351849.5 moles of air

Now, number of moles = mass/ molar mass

but molar mass = 28.97 g/mol

2351849.5 = mass/28.97

mass = 2351849.5 * 28.97

mass = 68133080.02 g

7 0
3 years ago
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