Answer:
Explanation:
<em>2. A 10 kg bowling ball would require what force to accelerate down an alleyway at a rate of 3m/s² ?</em>
Notice that I completed the question with the garbled and missing values:
<u>Data:</u>
<u />
<u>Physical principles:</u>
- Newton's second law:
<u>Solution:</u>
<em></em>
<em>3. Salty has a car that accelerates at 5 m/s². If the car has a mass of 1000 kg, how much force does the car produce?</em>
Notice that I arranged the typos.
<u />
<u>Data:</u>
<u>Physical principles:</u>
- Newton's second law:
<u>Solution:</u>
<em>4. What is the mass of a falling rock if it produces a force of 147 N?</em>
<u>Data:</u>
<u>Physical principles:</u>
- neglecting air resistance ⇒ a = g: gravitational acceleration: 9.8m/s²
- Newton's second law:
<u>Solution:</u>
- Clear m from Newton's second law
- Substitute with F = 147 N and a = g = 9.8m/s², and compute
<em></em>
<em>5. What is the mass of a truck if it produces a force of 14,000 N while accelerating at a rate of 5 m/s²?</em>
<u>Data:</u>
<u>Physical principles:</u>
- Second Newton's law:
<u>Solution:</u>
- Clear m from Newton's second law
- Substitute with F = 14,000 N and a = 5m/s², and compute
Answer:
The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg
Explanation:
Heat gain by ice = Heat lost by water
Thus,
Heat of fusion +
Where, negative sign signifies heat loss
Or,
Heat of fusion +
Heat of fusion = 334 J/g
Heat of fusion of ice with mass x = 334x J/g
For ice:
Mass = x g
Initial temperature = 0 °C
Final temperature = 6 °C
Specific heat of ice = 1.996 J/g°C
For water:
Volume = 353 mL
Density of water = 1.0 g/mL
So, mass of water = 353 g
Initial temperature = 26 °C
Final temperature = 6 °C
Specific heat of water = 4.186 J/g°C
So,
345.976x = 29553.16
x = 85.4197 kg
Thus,
<u>The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg</u>
Answer:
give me a min I learned this
True
water will turn into hydrogen and oxygen gas when electrified