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WITCHER [35]
2 years ago
11

Geometry 1.4 - Segment Addition Postulate & Midpoint

Mathematics
1 answer:
Roman55 [17]2 years ago
4 0

Answer:

28

Step-by-step explanation:

AB + BC = AC

14 + 3x-4 = 4x+4

Combine like terms

10 +3x = 4x+4

Subtract 3x from each side

10+3x-3x = 4x+4-3x

10 = x+4

Subtract 4 from each side

10-4 =x-4+4

6 =x

We want AC

AC = 4x+4 = 4*6+4 = 24+4 = 28

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3 years ago
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Answer:

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Step-by-step explanation:

because that the answer

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3 years ago
Evaluate the piecewise function for the given values.
adoni [48]

Answer:

f(-3) = -2

f(-2.6) = -2

f(0.6) = 2.4

f(4.5) = 8.5

Step-by-step explanation:

(Whole question:

Evaluate the piecewise function for the given values.

Find f(-3), f(-2,6), f(0.6), and f(4.5) for f(x)={ -2 If x ≤ 0 4x. If 0 <x <1. x + 4. If x ≥ 1)

As the piecewise function shows, the function f(x) has the value of -2 for values of x lesser or equal than 0, has the value of 4x if the value of x is between 0 and 1, and has the value of x+4 for values of x greater or equal than 1.

So, for f(-3), the value of x is lesser than 0, so we have that f(-3) = -2

For f(-2.6), the value of x is lesser than 0, so we have that f(-3) = -2

For f(0.6), the value of x is between 0 and 1, so we have that f(0.6) = 4*0.6 = 2.4

For f(4.5), the value of x is greater than 1, so we have that f(4.5) = 4.5 + 4 = 8.5

5 0
2 years ago
given the vector v has an initial point (-2,-6) and a terminal point of (1,2) write vector v as a linear combination of the stan
Anuta_ua [19.1K]

Answer:

v=3i+8j

Step-by-step explanation:

The given the vector v has an initial point (-2,-6) and a terminal point of (1,2).

To find the components of vector v, we subtract the terminal points from the initial point to obtain.

v=<1,2>-<-2,-6>

v=<1--2,2--6>

v=<1+2,2+6>

v=<3,8>

As a linear combination of the standard unit vectors.

v=3i+8j

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3 years ago
Simplify Negative 3 over 2 divided by 9 over 6.
Montano1993 [528]

Answer:

-2

Step-by-step explanation:

5 0
3 years ago
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