Answer:
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
Step-by-step explanation:
We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.
Firstly, Let X = women's gestation period
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= average gestation period = 270 days
= standard deviation = 9 days
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X
261)
P(X < 279) = P(
<
) = P(Z < 1) = 0.84134
P(X
261) = P(
) = P(Z
-1) = 1 - P(Z < 1)
= 1 - 0.84134 = 0.15866
<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>
Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
To solve this, find the rest of the sides:
The other sides are:
1. 24 - 8 = 16
2. 23 - 9 = 14
Next, just add it up:
24 + 9 + 16 + 14 + 8 + 23 = 33 + 30 + 31 = 94
Answer:
Step-by-step explanation:
Find the mean, median, mode, and range of the data 10, 13, 7, 6, 9, 4, 6, 3, 5
elena-s [515]
Median is 6 range is 9 mode is 6 and mean is 7
2y-6=34 is the needed equation