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Alona [7]
3 years ago
12

What would you need to lower to change a gas to a liquid

Chemistry
1 answer:
IrinaVladis [17]3 years ago
5 0

The temperature or the average kinetic energy of the molecules

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One mole of carbon will have the same number of particles as one mole of hydrogen.
AVprozaik [17]
And the answer is False,it does not have the same number with particles as the one mole of hydrogen.
3 0
3 years ago
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H2 + O2 ---&gt; H2O<br> Classifying reaction
Degger [83]

Answer:

hydrogen + oxygen = water

3 0
3 years ago
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This image shows the development of what climate phenomenon?
Tpy6a [65]

Answer:

Rain shadow

Explanation:

Climate is the average weather condition of a place over a long period of time.

The image shows a rain shadow effect around a mountainous region. The type of rainfall controlled this way is known as an orographic rainfall.

  • On the leeward side which is the opposite side of where the rain cloud forms, there is dryness and lack of rainfall.
  • As moist air rises along the edge of the windward side, cloud forms.
  • This windward side receives a significant amount of rainfall
  • The windward side is hit with cold and dry wind and it is barren.
8 0
3 years ago
You have 4 moles of oxygen gas in a flask. 4 moles of helium gas is added. What happens to the total pressure of the gases in th
ASHA 777 [7]

Answer: The correct option is (c). The total pressure doubles.

Solution:

Initially,  only 4 moles of oxygen gas were present in the flask.

p_{O_2}=Tp_1\times X_{O_2}  (X_{O_2}=\frac{4}{4}) ( according to Dalton's law of partial pressure)

p_{O_2}=Tp_1\times 1=Tp_1....(1)

Tp_1= Total pressure when only oxygen gas was present.

Final total pressure when 4 moles of helium gas were added:

X'_{O_2}=\frac{4}{8}=\farc{1}{2},X_{He}=\frac{4}{8}=\frac{1}{2}

partial pressure of oxygen in the mixture :

Since, the number of moles of oxygen remains the same, the partial pressure of oxygen will also remain the same in the mixture.

p_{O_2}=Tp_2\times X'_{O_2}=Tp_2\times \frac{1}{2}

Tp_2= Total pressure of the mixture.

from (1)

Tp_1=Tp_2\times X'_{O_2}=Tp_2\times \frac{1}{2}

On rearranging, we get:

Tp_2=2\times Tp_1

The new total pressure will be twice of initial total pressure.

7 0
3 years ago
Determine how many grams of N2 are produced from the reaction of 8.37 g of H2O2 and 5.29 g of N2H4.
Dmitriy789 [7]
N₂H₄  +  2H₂O₂    →   N₂  +  4H₂O

mol = mass ÷ molar mass

If mass of hydrazine (N₂H₄)  = 5.29 g 
then mol of hydrazine           = 5.29 g ÷ ((14 ×2) + (1 × 4))
                                              = 0.165 mol

mole ratio of hydrazine to Nitogen is     1   :  1
  ∴ if moles of hydrazine = 0.165 mol
     then moles of nitrogen = 0.165 mol

Mass = mol × molar mass

Since mol of nitrogen (N₂)  = 0.165
then mass of hydrazine      = 0.165 × (14 × 2)
                                           = 4.62 g
5 0
3 years ago
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