M=n/V , 4.5=n/1.5 , (45/10). (15/10)=n , (9/2).(3/2)=n=27/4 , n=6,75
Answer:
Major Product = 4-chloro-4-methylcyclohex-1-ene
Explanation:
Alkene are the class of organic compounds which contain one or more double bonds between two carbon atoms. Alkenes are considered most reactive among the unsaturated hydrocarbons and they undergo <em>addition reactions</em> due to high electron density around the double bonds.
In given question it is written that we are provided with one equivalent of HCl while, our compound contains two double bonds (diene) so in selected starting material the HCl will be added across (hydrohalogenation reaction) the substituted double bond because it will give a more stable carbocation (<u><em>tertiary carbocation</em></u>) during the reaction course. Hence, as shown in reaction scheme 4-chloro-4-methylcyclohex-1-ene will be the major product.
Sufficient energy upon collision of particles and correct orientation of particles
Answer:
weak bases
Explanation:
Leaving groups accept electron pairs. A strong base donates an electron pair while a weak base accepts an electron pair.
Since good leaving groups must readily accept electrons, weak bases are very good leaving groups.
The order of usefulness of halogens as leaving groups is: I > Br > Cl > F