Answer:
88,88 % de O y 11,11 % de H
Explanation:
La composición porcentual se define como la masa que hay de cada mol de átomo en 100g. Las moles de agua en 100g son:
<em>Masa molar agua:</em>
2H = 2*1g/mol = 2g/mol
1O = 1*16g/mol = 16g/mol
Masa molar = 2 + 16 = 18g/mol
100g H2O * (1mol / 18g) = 5.556 moles H2O.
Moles de hidrógeno:
5.556 moles H2O * (2mol H / 1mol H2O) = 11.11 moles H
Moles Oxígeno = Moles H2O = 5.556 moles
La masa de hidrógeno es:
11.11mol * (1g/mol) 11.11g H
La masa de oxígeno es:
5.556 mol * (16g / 1mol) = 88.89g O
Así, el porcentaje de O es 88.89% y el de H es 11.11%. La opción correcta es:
<h3>88,88 % de O y 11,11 % de H</h3>
Explanation:
It is known that the specific heat capacity of Liver
is 3.59 kJ
It is given that :
Initial temperature of Liver = Body temperature =
= 310 K
Final temperature of Liver = 180 K
Relation between heat energy, mass, and change in temperature is as follows.
Q =
Now, putting the given values into the above formula as follows.
Q = ![m \times C_{p} \times \Delta T](https://tex.z-dn.net/?f=m%20%5Ctimes%20C_%7Bp%7D%20%5Ctimes%20%5CDelta%20T)
Q =
= 700.05 kJ
Therefore, we can conclude that amount of heat which must be removed from the liver is 700.05 kJ.
<u>Answer:</u> The percent composition of hydrogen in the sample is 15.22 %
<u>Explanation:</u>
We are given:
Mass of hydrogen = 7 grams
Mass of nitrogen = 32 grams
Mass of carbon = 7 grams
Total mass of the sample = 7 + 32 + 7 = 46 grams
To calculate the percentage composition of hydrogen in sample, we use the equation:
![\%\text{ composition of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of sample}}\times 100](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20composition%20of%20hydrogen%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20hydrogen%7D%7D%7B%5Ctext%7BMass%20of%20sample%7D%7D%5Ctimes%20100)
Mass of sample = 46 g
Mass of hydrogen = 7 g
Putting values in above equation, we get:
![\%\text{ composition of hydrogen}=\frac{7g}{46g}\times 100=15.22\%](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20composition%20of%20hydrogen%7D%3D%5Cfrac%7B7g%7D%7B46g%7D%5Ctimes%20100%3D15.22%5C%25)
Hence, the percent composition of hydrogen in the sample is 15.22 %
Answer:
Mass of oxygen required = 19.5 moles × 16 g/mol = 312 g.
Explanation:
When u give supply to a coil then a current will be passed through it .
<span>naturally a magnetic field is produced around the c.c.c(current carrying conductor). when u make more turns in the same direction the whole magnetic field will be stronger than that of a wire has. and </span>
<span>by lenz's law there will be an opposition to the changing current in a coil due to the change in magnetic field produced</span>