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katrin2010 [14]
2 years ago
15

Hola alguien me puede ayuda esto no se como

Chemistry
1 answer:
Readme [11.4K]2 years ago
6 0
Para convertir c a kelvin
K=c +273
Ósea que en vez de c vas a poner el número

Para de Kevin a Celsius
C=k - 273
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A chemist dilutes 185 of the 3.0 M solution with water until a new volume of 750 is obtained. Calculate the new concentration
svlad2 [7]

Answer:

0.74M

Explanation:

Step 1 :

Data obtained from the question.

Initial concentration (C1) = 3M

Initial volume (V2) = 185mL

Final volume (V2) = 750mL

Final concentration (C2) =..?

Step 2:

Determination of the new concentration of the solution.

The new concentration of the solution can be obtained by using the dilution formula as shown below:

C1V1 = C2V2

3 x 185 = C2 x 750

Divide both side by 750

C2 = 3 x 185 / 750

C2 = 0.74M

Therefore, the new concentration of the solution is 0.74M

7 0
3 years ago
help please, How much water would you need to add to the 10 grams of sodium hydroxide to make 100 grams of the 10% solution?
jonny [76]

Answer:

90

Explanation:

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5 0
3 years ago
Which characteristics do Jupiter and Saturn share? Check all that apply
Natasha2012 [34]

Answer:

The correct answers are first, fourth, fifth

Explanation:

6 0
3 years ago
Read 2 more answers
8. A 15.0 gram unknown piece of metal at 99 oC is added to 75 grams of water at 23 oC. The final temperature of the metal and wa
Setler79 [48]

The specific heat of the unknown metal is 0.859 J/g⁰C.

<h3>Specific heat of the unknown metal</h3>

Heat lost by the unknown metal = Heat gained by water

m₁c₁Δθ₁ = m₂c₂Δθ₂

where;

  • c₁ is specific heat of the unknown metal
  • c₂ is specific heat of water

(15)(c₁)(99 - 26) = (75)(4.18)(26 - 23)

1095c₁ = 940.5

c₁ = 940.5/1095

c₁ = 0.859 J/g⁰C

Learn more about specific heat here: brainly.com/question/16559442

#SPJ1

3 0
2 years ago
A sample of ethanol has a volume of 7.5 mL and a mass of 5.85 g. A sample of benzene also has a volume of 7.5 ml,
AysviL [449]

Answer:

Benzene

Explanation:

You need to calculate the densities for each compound.

EtOH = 5.85/7.5 = 0.78 g/mL

Benzene = 6.60/7.5 = 0.88 g/mL

0.88 > 0.78, thus benzene is denser than ethanol.

3 0
3 years ago
Read 2 more answers
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