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EleoNora [17]
2 years ago
12

HELP ME PLEASE i need this thing really fast

Mathematics
2 answers:
sergejj [24]2 years ago
5 0

Answer:

h(x - 1) + 2

h( - 3+ 1) + 2

h \times  - 4 + 2

- 4h + 2

marysya [2.9K]2 years ago
4 0
-22 trust I did that on khan
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What is the equation of the line that passes<br> through the point (3, 4) and has a slope of -2/3
Rina8888 [55]

Answer:

y=-2/3x+6

Step-by-step explanation:

y-y1=m(x-x1)

y-4=-2/3(x-3)

y=-2/3x+6/3+4

y=-2/3x+2+4

y=-2/3x+6

6 0
2 years ago
Alice's grandmothers age is a composite number between 70 and 80 and has a factor of 11 what is it
pshichka [43]

The factor of 11 is going to be 77 because you have to stay in between 70 to 80

and 7 times 11 is 77. It also has to be a number in the 11 timetables. It can't be 88 because we can't cross 80 so the factor is going to be 77.


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3 years ago
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Answer:

Step-by-step explanation:

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2 years ago
Determine which problem matches the given inequality.
sergey [27]

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8 0
3 years ago
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EasyElectrics supermarket orders light bulbs from suppliers, AA Electronics and AAA Electronics. EasyElectrics purchases 30% of
saw5 [17]

Answer: (a) 0.006

               (b) 0.027

Step-by-step explanation:

Given : P(AA) = 0.3 and P(AAA) = 0.70

Let event that a bulb is defective be denoted by D and not defective be D';

Conditional probabilities given are :

P(D/AA) = 0.02 and P(D/AAA) = 0.03

Thus P(D'/AA) = 1 - 0.02 = 0.98

and P(D'/AAA) = 1 - 0.03 = 0.97

(a) P(bulb from AA and defective) = P ( AA and D)

                                                       = P(AA) x P(D/AA)

                                                       = 0.3 x 0.02 = 0.006

(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)

                         = P(AA) x P(D/AA) + P(AAA) x P(D/AAA)

                         = 0.3(0.02) + 0.70(0.03)

                         = 0.027

3 0
3 years ago
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