The answer is going to be A
Answer:
Step-by-step explanation:
Prime factorization: 43 is prime. The exponent of prime number 43 is 1. Adding 1 to that exponent we get (1 + 1) = 2. Therefore 43 has exactly 2 factors.
Answer:
Evaluate ∫3x2sin(x3)cos(x3)dx
Step-by-step explanation:
hello (a) using the substitution u=sin(x3) because
du =3x²(cos x3)dx
you have ∫3x2sin(x3)cos(x3)dx = ∫udu=u²/2 +c............continu
