what will happen to the gravitational force between two bodies if the distance between them is halved keeping their masses const
1 answer:
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Answer:
1)
2) x = 0.28 m from cable A.
Explanation:
1 ) Let's use the first Newton to find the , because bar is in equilibrium.
In this case we just have y-direction forces.
Now, let's solve the equation for W(object).
2 ) To find the position of the heaviest weight we need to use the torque definition.
The total torque is evaluated in the axes of the object.
Let's put the heaviest weight in a x distance from the cable A. We will call this point P for instance.
First let's find the positions from each force to the P point.
; total length of the bar.
; distance between Tension A and P point.
; distance between Tension B and P point.
; distance between weight of the bar (middle of the bar) and P point.
Now, let's find the total torque in P point, assuming counterclockwise rotation as positive.
Finally we just need to solve it for x.
So the distance is x = 0.28 m from cable A.
Hope it helps!
Have a nice day! :)
Answer:
a
This a closed system because the mass of the system is conserved
The energy system that undergoes change is the Potential energy system
The energy system diagram is shown on the first uploaded image
b
Work done = Change in gravitational potential energy
So solving algebraically for work done would be
Work done =
where m is mass
g is acceleration due to gravity
and h is the height
c
Work done in terms of force and distance is = mg
where m is mass of bucket and
g is acceleration due to gravity
Explanation:
a) At the start, potential and kinetic energy were zero. so, energy is zero.
As the person pulls the bucket up, the potential energy becomes mgh.
so,final energy will be consisting of only potential energy.
B) Here work done is equal to change in gravitational potential energy.
W =
W = m*g*h
where g = 9.9 m/
C) Work = force * distance
mgh = force * h
force = mg
force = weight of bucket
