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3 years ago

Specialized businesses that help coordinate dealings between other companies are called:

Physics

1 answer:

sineoko [7]3 years ago

3 0

Answer:

The answer would be Agencies. This is grade 2 stuff.

Explanation:

Please mark me Brainliest.

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For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The larg

jeyben [28]

Answer:

<h2>Magnetic field strength in that region is 1.2 T</h2>

Explanation:

As we know by the formula of radius of charge moving in external field is given as

$R = \frac{mv}{qB}$

so we will have

$R = 25 cm$

$m = 1.6 \times 10^{-27} kg$

$q = 1.6 \times 10^{-19} C$

$v = 0.10 \times 3 \times 10^8 m/s$

now we have

$0.25 = \frac{(1.6 \times 10^{-27})(3\times 10^7)}{(1.6 \times 10^{-19})B}$

now we have

$B = 1.2 T$

8 0

3 years ago

Jannah is looking for an internship that will advance and support her love of astronomy. She is 17 years old, has a 4.0 GPA, and

Dennis_Churaev [7]

I would say NASA because she wants to her hands on + there is a NASA research center in Hampton, Virginia!

6 0

4 years ago

In february a little town received snow on a daily basis. The first day they had 10 inches, 3 inches the second, 7 inches the 3r

viktelen [127]

Answer:

Explanation:

Add 10+7+3+4 and then divide your answer by 4

5 0

3 years ago

Read 2 more answers

A baseball has 5.8kg*m/s momentum before being hit by the bat. After being hit it has 6.79 kg*m/s in the opposite direction. Wha

fomenos

Answer:

0.99kgm/s

Explanation:

Given parameters:

Initial momentum = 5.8kgm/s

Final momentum = 6.79kgm/s

Unknown:

Magnitude of the impulse applied to the baseball = ?

Solution:

To solve this problem;

The impulse applied to the baseball can be found by using the expression below:

Impulse = Final momentum - Initial momentum

Impulse = 6.79kgm/s - 5.8kgm/s = 0.99kgm/s

8 0

3 years ago

Aluminum rivets used in airplane construction are made slightly larger than the rivet holes and cooled by "dry ice" (solid CO2)

poizon [28]

Answer:

$\rm 4.554\ m m.$

Explanation:

<u>Given:</u>

Initial temperature, $\rm T_i=23.0\ ^\circ C=23 + 273.15 = 296.15\ K.$
Final temperature, $\rm T_f = -78.0\ ^\circ C = -78+273.15=195.15\ K.$
Diameter of the hole, $\rm d = 4.500\ m = 4.500\times 10^{-3}\ m.$
Expansion coefficient of the Aluminum, $\rm \alpha = 2.4\times 10^{-5}\ K^{-1}.$

Let the diameter of the rivet at $\rm T_i=23.0\ ^\circ C$ be $\rm d_o$ , such that,

$\rm d_o=d+\Delta d$

$\rm \Delta d$ is the elongation in the diameter of the rivet.

We know, The change in the diameter of the rivet is related with the change in temperature as:

$\rm \dfrac{\Delta d}{d_o}=\alpha \Delta T.$

where, $\rm \Delta T$ is the change in temperature = $\rm T_f-T_i=-195.15-296.15=-491.30\ K.$

Also, $\rm \Delta d=d_o-d.$

Using these values,

$\rm \dfrac{d_o-d}{d_o}=\alpha \Delta T\\1-\dfrac{d}{d_o}=\alpha \Delta T\\\dfrac{d}{d_o}=1+\alpha \Delta T\\\Rightarrow d_o = \dfrac{d}{1+\alpha \Delta T}\\=\dfrac{4.500\times 10^{-3}}{1+2.4\times10^{-5}\times (-491.30)}\\=4.554\times 10^{-3}\ m.\\=4.554\ m m.$

It is the required diameter of the rivet at $-78.0\ ^\circ C$ .

4 0

3 years ago