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2 years ago

Specialized businesses that help coordinate dealings between other companies are called:

Physics

1 answer:

sineoko [7]2 years ago

3 0

Answer:

The answer would be Agencies. This is grade 2 stuff.

Explanation:

Please mark me Brainliest.

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Exam

Sedaia [141]

Out put work
explanation:

3 0

3 years ago

Read 2 more answers

Find the angle of prism if the ray just fail to emerge from 2nd face When ray of light falls normallly on the face of prism of R

Usimov [2.4K]

The angle of prism is 41.81 degrees.

<u>Explanation:</u>

For no emergence to be taken place, inside a prism, Total Internal Reflection (TIR) should take place at the second surface. For TIR, at second surface, angle of refraction must be greater than critical angle. Angle of prism is related to refraction as,

$A>r_{1}+C$

Since, $r_{1}$ = C and $A \geq 2 C$

This implies $A \geq C$

$\sin A \geq \sin C$

$\sin A \geq \frac{1}{\mu}$

$\sin A \geq \frac{2}{3}$

when sin goes to other side become as sin inverse of value, and obtain the result as below,

$A=41.81^{\circ}$

3 0

3 years ago

Which of the following are true? Select all that apply. The net electric field at any location inside a block of copper is zero

Agata [3.3K]

Answer:

1) The net electric field at any location inside a block of copper is zero if the copper block is in equilibrium.

2) In equilibrium, there is no net flow of mobile charged particles inside a conductor.

3) If the net electric field at a particular location inside a piece of metal is not zero, the metal is not in equilibrium.

Explanation:

1) and 3) A block of copper is a conductor. The charged particles on a conductor in equilibrium are at rest, so the intensity of the electric field at all interior points of the conductor is zero, otherwise, the charges would move resulting in an electric current.

2) The charged particles on a conductor in equilibrium are at rest.

6 0

3 years ago

The 45-g arrow is launched so that it hits and embeds in a 1.40 kg block. The block hangs from strings. After the arrow joins th

worty [1.4K]

Question: How fast was the arrow moving before it joined the block?

Answer:

The arrow was moving at 15.9 m/s.

Explanation:

The law of conservation of energy says that the kinetic energy of the arrow must be converted into the potential energy of the block and arrow after it they join:

$\dfrac{1}{2}m_av^2 = (m_b+m_a)\Delta Hg$

where $m_a$ is the mass of the arrow, $m_b$ is the mass of the block, $\Delta H$ of the change in height of the block after the collision, and $v$ is the velocity of the arrow before it hit the block.