Answer:
27: 85
28:75%
Explanation:
27:68=80
?=100 hence (68×100)÷80
=85
28:<em>1</em><em>8</em><em>/</em><em>2</em><em>4</em><em>×</em><em> </em><em>1</em><em>0</em><em>0</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>7</em><em>5</em><em>%</em>
Answer:
Explanation:
Let the height of the tree is y and the distance of tree from point B is x.
According to the diagram

x = 0.55 y ..... (1)

(50 + 0.55y) 1.17 = y ..... from equation (1)
58.5 + 0.644 y = y
0.356 y = 58.5
y = 164.3 ft
The potential at a distance r from a charge Q is given by

where ke is the Coulomb's constant.
The charge in our problem is

; for the point at

, the potential is

For the point at infinity, we immediately see that the potential is zero, because

and so

.
Therefore, the potential difference between the two points is