Answer:
Explanation:
Pipet is used to dispense a very small amount of liquid.
Test tube rack is used to hold multiple test tubes at the same time.
Test Table is used to view chemical reactions or hold or heat small amounts of substance.
Scoopula is used to dispense chemicals from a larger container.
Graduated cylinder is used to measure volume very precisely.
Bunsen burner is used to heat objects.
Beaker is used to transport heat or store substance.
Spot plate is used to observe the color changes of small quantities of a reacting mixture.
Goggles are used to protect the eyes from flying objects or chemical splashes.
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Describe the process by which Ag+ ions are precipitated out of solution. 4. In your testing, several precipitates are formed, and then dissolved as complexes.
Answer:
Mass = 157.5 g
Explanation:
Given data:
Mass of CO needed = ?
Mass of Fe formed = 209.7 g
Solution:
Chemical equation:
3CO + F₂O₃ → 2Fe + 3CO₂
Number of moles of Fe:
Number of moles = mass/ molar mass
Number of moles = 209.7 g/ 55.85 g/mol
Number of moles = 3.75 mol
Now we will compare the moles of iron and carbon monoxide.
Fe : CO
2 : 3
3.75 ; 3/2×3.75 = 5.625 mol
Mass of CO:
Mass = number of moles × molar mass
Mass = 5.625 mol × 28 g/mol
Mass = 157.5 g
Answer:
Q1) Distillation relies on evaporation to purify water
Explanation:
contaminated water is heated to form steam. inorganic compounds and large non-volatile organic molecules do not evaporate with the water and are left behind. The steam then cools and condenses to form purified water
Answer:
67.492cm^3
Explanation:
To get the volume of tetrahydrofuran needed, what the student need to do is to apply mathematical calculations.
We know quite well that to obtain the volume of a substance, given the mass of the substance and the density of the substance is possible.
The volume of the substance is simply the mass of the substance divided by the density of the substance.
This is thus volume = mass/density
The mass given is the question is 60g while the density given is 0.889g/cm^3
The volume = 60/0.889 = 67.492cm^3
