<u>Examples of energy:</u> Nuclear, Fossil Fuels, Solar, Wind, Hydroelectric, Geothermal, Kinetic, Mechanical, Potential, and Chemical.
<u>Non-examples:</u> love, atoms, hatred, air, matter, ideas, socket, and batteries.
Answer:
6.88 mg
Explanation:
Step 1: Calculate the mass of ³²P in 175 mg of Na₃³²PO₄
The mass ratio of Na₃³²PO₄ to ³²P is 148.91:31.97.
175 mg g Na₃³²PO₄ × 31.97 g ³²P/148.91 g Na₃³²PO₄ = 37.6 mg ³²P
Step 2: Calculate the rate constant for the decay of ³²P
The half-life (t1/2) is 14.3 days. We can calculate k using the following expression.
k = ln2/ t1/2 = ln2 / 14.3 d = 0.0485 d⁻¹
Step 3: Calculate the amount of P, given the initial amount (P₀) is 37.6 mg and the time elapsed (t) is 35.0 days
For first-order kinetics, we will use the following expression.
ln P = ln P₀ - k × t
ln P = ln 37.6 mg - 0.0485 d⁻¹ × 35.0 d
P = 6.88 mg
Rutherford came to this conclusion after his Gold-Foil experiment. He found that most of the alpha particales(when released) went straight through the gold foil, of which consisted of atoms. In the middle of the atom theres a small nucleus that has mass and positive charge. Because the nucleus is so small the alpha <span>particles were able to go straight through leading to the conclusion that atoms are mostly empty space. </span>
Explanation:
divide the objects weight by the acceleration of gravity to find the mass
