I think pulley, leaver, and screws
Answer:
ωf = 8.8 rad/s
v = 2.2 m/s
Explanation:
We will use the third equation of motion to find the maximum angular velocity of the wheel:
where,
α = angular acceleration = 6 rad/s²
θ = angular displacemnt = 1 rev = 2π rad
ωf = max. final angular velocity = ?
ωi = initial angular velocity = 1.5 rad/s
Therefore,
<u>ωf = 8.8 rad/s</u>
Now, for linear velocity:
v = rω = (0.25 m)(8.8 rad/s)
<u>v = 2.2 m/s</u>
It made the development of cars, trucks, and airplanes possible.
Answer:
5 Newtons Up and 5 Newtons Right
Explanation:
Treat each force vector as a value and choose the upward and rightward directions to be positive. Downward and Leftward forces will be considered "negative". For the vertical net force we have a positive 10 N upwards and a negative 5 N downwards. The net force in the vertical will be 5 N upwards. In the horizontal we have 10 N to the right and 5 N to the left. The net force in the horizontal will be 5 N to the Right.
It is easier if you split the motion into horizontal and vertical components.
Answer: 43.01 m
Explanation:
Given that :
Time ball uses in the air = 5.93, time it takes to reach maximum height and return = time of flight(T) = 5.93 s
TIME of flight (T) = 2 * time taken(t)
Where g = a = acceleration due to gravity = 9.8m/s²
S = 0.5at²
S = maximum height
Tjme taken (t) = time of flight / 2 = 5.93/2 = 2.965 s
Hence,
S = 0.5at²
S = 2 × 0.5 × 9.8 × 2.965²
S = 43.0770025
S = 43.01 m