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fgiga [73]
4 years ago
9

The rate at which an object’s velocity changes is called its

Physics
2 answers:
ANTONII [103]4 years ago
7 0

Answer:

Acceleration

Explanation:

topjm [15]4 years ago
6 0
I believe it is call “Acceleration”
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A three branch parallel circuit has resistors of 27 W, 56 W, and 15 W. What is the total resistance?
Mekhanik [1.2K]

Answer:8.2 Ω

Explanation:

I ASSUME you mean Ω (ohms) and not W(atts)

Re = 1/(1 / 27 + 1/56 + 1/15) = 8.2263329... ≈ 8.2 Ω

6 0
3 years ago
Kepler's discoveries regarding the motions of the planets were based on the observations of
Helga [31]
Kepler's hypothesis to describe the motions of the planets was derived from
the meticulous observations performed and recorded by Tycho Brahe.
4 0
3 years ago
The final velocity of car is 20 m/s. The car is accelerating at a rate of 2.5m/s over a 10 seconds period of time. What is the i
balu736 [363]

Answer:

-5m/s

Explanation:

Since

acceleration=final velocity-initial velocity/time

2.5m/s^2=20m/s- initial velocity/10s

2.5m/s^2×10s= 20m/s -initial velocity

25m/s=20m/s - initial velocity

Initial velocity=20m/s-25m/s

= -5m/s

4 0
3 years ago
In a tug of war , two teams pull on the rope with a certain force. If team A pulls on it with a force of 225 N and team B pulls
kherson [118]

Answer:

135 N

Explanation:

Given that:

In a tug of war, team A pulls the rope with a force of 225 N; &

Team B also pulls with a force of 360 N

The magnitude of the resultant force is the difference between the two forces since they are positioned in the opposite direction.

Thus;

The magnitude = 360 N - 225 N

So, magnitude of resultant force on the rope = 135 N

8 0
3 years ago
Children slide down a frictionless water slide that ends at a height of 1.80 m above the pool. If a child starts from rest at po
Lerok [7]

Answer:

h = 1.75 m

Explanation:

As we know that height of the slide is given as

h = 1.80 m

so time taken by the child to hit the water from the slide is given as

t = \sqrt{\frac{2h}{g}}

now we will plug all data in it

t = \sqrt{\frac{2(1.80)}{9.81}}

t = 0.605 s

now we know that the horizontal distance moved by it is given as

L = v_x t

3.55 = 0.605 v_x

v_x = 5.86 m/s

now by energy conservation

mgh = \frac{1}{2}mv^2

so height of point A is given as

h = \frac{v_x^2}{2g}

h = \frac{5.86^2}{2(9.81)}

h = 1.75 m

3 0
3 years ago
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