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fgiga [73]
3 years ago
9

The rate at which an object’s velocity changes is called its

Physics
2 answers:
ANTONII [103]3 years ago
7 0

Answer:

Acceleration

Explanation:

topjm [15]3 years ago
6 0
I believe it is call “Acceleration”
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You have been hired to design a spring-launched roller coaster that will carry two passengers per car. The car goes up a 12-m-hi
Vlada [557]

Answer:

Vmax=11.53 m/s

Explanation:

from conservation of energy

      E_A} =E_{B}

     Spring potential energy =potential energy due to elevation

   0.5*k*x²= mg(h_{B}-h_{A} )=mgh

   0.5*k*2.3²= 430*9.81*6

         k=9568.92 N/m

For safety reason

                                 k"=1.13 *k= 1.13*9568.92

                                    k"=10812.88 N/m

agsin from conservation of energy

      E_A} =E_{C}

    spring potential energy=change in kinetic energy

   0.5*k"*x²=0.5*m*V_{max}^{2}

      10812.88 *2.3²=430*V_{max}^{2}

           V_{max}=11.53 m/s

5 0
3 years ago
WILL GIVE BRAINLY!!!
Gnoma [55]
The answer is apogee my dude
7 0
3 years ago
The linear impulse delivered by the hit of a boxer is 202 N · s during the 0.244 s of contact. What is the magnitude of the aver
zlopas [31]

Answer: Magnitude of the average force exerted on the glove by the other boxer is 827.86 N (approximately 828 N).

Explanation: Impulse is defined as the force acting on an object for a short period or interval of time.

Mathematically it is given by the relation:

Impulse = Force \times Time

According to the numerical values given in the question, I = 202 Ns and T = 0.244 s

So, Force F = \frac{Impulse}{Time} = \frac{202}{0.244} = 827.86 N

Magnitude of the average force exerted on the glove by the other boxer is 827.86 N (approximately 828 N).

7 0
3 years ago
The most common isotope of hydrogen contains a proton and an electron 'separated by about -11-27 5.0 x 10 m. The mass of proton
Brrunno [24]

Answer:

A)   F_g = 4.05 10⁻⁴⁷ N, B)   F_e = 9.2 10⁻⁸N, C)    \frac{F_e}{F_g} = 2.3 10³⁹

Explanation:

A) It is asked to find the force of attraction due to the masses of the particles

Let's use the law of universal attraction

            F = G \frac{m_1m_2}{r^2}

let's calculate

            F = 6.67 \ 10^{-11} \ \frac{9.1 \ 10^{-31} \ 1.67 \ 10 ^{-27} }{(5 \ 10^{-11})^2 }

            F_g = 4.05 10⁻⁴⁷ N

B) in this part it is asked to calculate the electric force

Let's use Coulomb's law

            F = k \  \frac{q_1q_2}{r^2}

let's calculate

            F = 9 \ 10^9 \  \frac{(1.6 \ 10^{-19} )^2}{(5 \ 10^{-11})^2}

             F_e = 9.2 10⁻⁸N

C) It is asked to find the relationship between these forces

        \frac{F_e}{F_g} = \frac{9.2 \ 10^{-8} }{4.05 \ 10^{-47} }

        = 2.3 10³⁹

therefore the electric force is much greater than the gravitational force

4 0
3 years ago
The measurement of an exoplanet's radius is measured in units compared to ________.
sesenic [268]
The eaths radius is the correct answer, if you need proof look at nasa's website 

4 0
3 years ago
Read 2 more answers
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