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Andreyy89
3 years ago
6

Why do people put rough strips in their bathtubs?

Physics
1 answer:
krok68 [10]3 years ago
4 0

Answer:

hi, the reason is for friction so that they don't fall. subscribe to me on you tube. name is my brainly name

Explanation:

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a 1300-kilogram space vehicle travels at 4.8 meters per second along the level surface of mars. if the magnitude of the gravitat
Helga [31]

The magnitude of the normal force acting on the space vehicle will be 5070 newtons. So option (4) is correct.

Given that,

The mass of the space vehicle is 1300 kilograms

It travels at a speed of 4.8 meters per second along the level surface of mars.

The g' (gravitational field strength) on the surface of mars is 3.9 newtons per kilogram

We need to find the normal force acting on the space vehicle

We know, N = mg' (where N is normal force)

N = (1300 × 3.9) Newton

N = 5070 Newton

So, the magnitude of the normal force acting on the space vehicle that is traveling at 4.8 meters per second along the level surface of mars will be 5070 newtons.

The normal force is the force that surfaces exert to prevent solid objects from passing through each other. The normal force is one type of ground reaction force.

Learn more about the normal force here:

brainly.com/question/6922206

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5 0
1 year ago
Phase difference formula
Anestetic [448]

Answer:

Δx is the path difference between the two waves.

...

Phase Difference And Path Difference Equation.

Formula Unit

Phase Difference \Delta \phi=\frac{2\pi\Delta x}{\lambda } Radian or degree

Path Difference \Delta x=\frac{\lambda }{2\pi }\Delta \phi meter

3 0
3 years ago
You have a grindstone (a disk) that is 98.0 kg, has a 0.335-m radius, and is turning at 100 rpm, and you press a steel axe again
Alika [10]

Answer:

a=0.276

Explanation:

From the question we are told that:

Mass m=98.kg

Radius r=0.335

Angular velocity \omega=100rpm

Radial force of F_r=23.6 N.

Kinetic coefficient of friction  \mu=0.192

Generally the equation for Kinetic Force is mathematically given by

 F_k=\mu.F_r

 F_k=0.192*23.6

 F_k=4.5312

Generally the equation for Torque on Center is mathematically given by

 Ia=f_k*r

Where

 I=\frac{Mr^2}{2}

Therefore

 a=\frac{2f_k}{Mr}

 a=\frac{2*4.5312}{98*0.335}

 a=0.276

Therefore Angular acceleration of the grindstone is

a=0.276

4 0
2 years ago
What is it called when something doesn’t flow easy
LUCKY_DIMON [66]

Answer:

That something is called having a high viscosity.

Explanation:

The measure expressing a "resistance to flow" is called viscosity. Viscosity relates to  internal friction forces in a fluid causing it to flow with more or less difficulty. Highly viscous stuff is perceived "thick" or "sticky."

7 0
3 years ago
Two loudspeakers emit sound waves of the same frequency along the x-axis. The amplitude of each wave is a. The sound intensity i
leonid [27]

Answer:

Explanation:

To find the amplitude of the sound, we must first determine the wavelength and the phase difference between the two speakers.

For the wavelength;

Recall that, the separation between two successive max. and min. intensity points are \dfrac{\lambda}{2}

Thus; for both speakers; the wavelength of the sound is:

\dfrac{\lambda}{2} = (10+30) cm

\dfrac{\lambda}{2} = (40) cm

λ = 80 cm

The relation between the path difference(Δx) and the phase difference(Δ∅) is:

\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o

where;

Δx = 10 cm

λ = 80 cm

Δ∅ = π rad

∴

\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o

\pi \ rad  = \dfrac{2 \pi}{80 \ cm}(10 \ cm) + \Delta \phi_o

\pi \ rad  = \dfrac{2 \pi}{8}+ \Delta \phi_o

\pi \ rad  = \dfrac{ \pi}{4}+ \Delta \phi_o

\Delta \phi_o  =  \pi -\dfrac{ \pi}{4}

\Delta \phi_o  = \dfrac{ 4\pi - \pi}{4}

\Delta \phi_o  = \dfrac{ 3\pi}{4} \ rad

Suppose both speakers are placed side-by-side, then the path difference between the two speakers is: Δx = 0 cm

Thus, we have:

\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o

\Delta \phi = \dfrac{2 \pi}{\lambda}(0 \ cm ) + \dfrac{3 \pi}{4} \ rad

\Delta \phi = \dfrac{3 \pi}{4} \ rad

∴

The amplitude of the sound wave if the two speakers are placed side-by-side is:

A = 2a \ cos \bigg (\dfrac{\Delta \phi }{2} \bigg)

A = 2a \ cos \bigg (\dfrac{\dfrac{3 \pi}{4} }{2} \bigg)

A = 2a \ cos \bigg ({\dfrac{3 \pi}{8} } \bigg)

A = 0.765a

7 0
3 years ago
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