The magnitude of the normal force acting on the space vehicle will be 5070 newtons. So option (4) is correct.
Given that,
The mass of the space vehicle is 1300 kilograms
It travels at a speed of 4.8 meters per second along the level surface of mars.
The g' (gravitational field strength) on the surface of mars is 3.9 newtons per kilogram
We need to find the normal force acting on the space vehicle
We know, N = mg' (where N is normal force)
N = (1300 × 3.9) Newton
N = 5070 Newton
So, the magnitude of the normal force acting on the space vehicle that is traveling at 4.8 meters per second along the level surface of mars will be 5070 newtons.
The normal force is the force that surfaces exert to prevent solid objects from passing through each other. The normal force is one type of ground reaction force.
Learn more about the normal force here:
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Answer:
Δx is the path difference between the two waves.
...
Phase Difference And Path Difference Equation.
Formula Unit
Phase Difference \Delta \phi=\frac{2\pi\Delta x}{\lambda } Radian or degree
Path Difference \Delta x=\frac{\lambda }{2\pi }\Delta \phi meter
Answer:
Explanation:
From the question we are told that:
Mass 
Radius 
Angular velocity 
Radial force of 
Kinetic coefficient of friction 
Generally the equation for Kinetic Force is mathematically given by
Generally the equation for Torque on Center is mathematically given by
Where
Therefore
Therefore Angular acceleration of the grindstone is
Answer:
That something is called having a high viscosity.
Explanation:
The measure expressing a "resistance to flow" is called viscosity. Viscosity relates to internal friction forces in a fluid causing it to flow with more or less difficulty. Highly viscous stuff is perceived "thick" or "sticky."
Answer:
Explanation:
To find the amplitude of the sound, we must first determine the wavelength and the phase difference between the two speakers.
For the wavelength;
Recall that, the separation between two successive max. and min. intensity points are 
Thus; for both speakers; the wavelength of the sound is:
λ = 80 cm
The relation between the path difference(Δx) and the phase difference(Δ∅) is:
where;
Δx = 10 cm
λ = 80 cm
Δ∅ = π rad
∴
Suppose both speakers are placed side-by-side, then the path difference between the two speakers is: Δx = 0 cm
Thus, we have:
∴
The amplitude of the sound wave if the two speakers are placed side-by-side is:
A = 0.765a
