Question

During a baseball game, a batter hits a high

Answer 1

Answer: 43.01 m

Explanation:

Given that :

Time ball uses in the air = 5.93, time it takes to reach maximum height and return = time of flight(T) = 5.93 s

TIME of flight (T) = 2 * time taken(t)

Where g = a = acceleration due to gravity = 9.8m/s²

S = 0.5at²

S = maximum height

Tjme taken (t) = time of flight / 2 = 5.93/2 = 2.965 s

Hence,

S = 0.5at²

S = 2 × 0.5 × 9.8 × 2.965²

S = 43.0770025

S = 43.01 m