Deacreasing the mass of one objects.
Increasing the mass of one of the objects.
Deacreasing the distance between the objects. (hope this helps)
Explanation:
mass of copper block = 0.3 kg at 77 K or -196 °C
Let mass of water taken be m ( maximum) , in this case we will have mixture of water and copper block at 0°C finally.
Heat gained by copper block
= msΔt
.3 x 196 x 385 J
heat lost by water to lower its temp fro 50°C to 0°C
= m x 4186 x 50
Heat lost = heat gained
m x 4186 x 50 = .3 x 196 x 385
m = 108.16 gm
Let mass of water taken be m ( minimum ) , in this case we will have mixture of ice and copper block at 0°C finally.
heat lost by water to lower its temp fro 50°C to 0°C
= m x 4186 x 50
heat lost by water to lower its temp from 0°C to 0°C ice
= m x latent heat of fusion
m x 3.35 x 10⁵
Total heat lost
= m x 3.35 x 10⁵ + m x 4186 x 50
= 544300 m
Heat gained by copper block
= msΔt
.3 x 196 x 385 J
Heat lost = heat gained
544300 m = .3 x 196 x 385 J
m = 41.6 gm
Atoms, molecules, electrons, photons, protons etc.
Answer:
IMA = 2
Explanation:
Given the following data;
Resistance gear = 54 teeth
Effort gear = 23 teeth
To find the ideal mechanical advantage (IMA);
IMA = number of teeth on the resistance gear/number of teeth on the effort gear
Substituting into the equation, we have;
IMA = 54/23
IMA = 2.35 ≈ 2
Therefore, the ideal mechanical advantage (IMA) of this two-gear system is 2.
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