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3 years ago

Which would cause a hazard when working with chemicals in laboratory?

1 answer:

6 0

Hey there,
The answer is A, touching a chemical.
You need to wear gloves and safety googles when handling chemicals to prevent any hazards.

Hope this helps :))

<em>~Top♥</em>

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The production of new skin cells to replace those that have been lost is an example of what characteristic of life?

Alchen [17]

The production of new skin cells is example of regeneration.

Regeneration is process of replacing or restoring not just skin cells, but also other cells in the human organism.

Skin regeneration is replacement of damaged tissue with new tissue.

There are two ways of skin regeneration:

1) reconstruction is a process of rebuilding of damaged skin cells

2) restoration is process of replacing broken cell skins

Epidermal stem cells are those who produces new daughter cell skins.

Epidermal stem cells are in the lowest layer of the skin.

More about skin: brainly.com/question/306377

#SPJ4

5 0

1 year ago

What is the chemical composition of hot chocolate?

iris [78.8K]

Answer:

Hot chocolate is as straightforward as drinks go: at its core, it's milk, cocoa powder, and sugar. Despite its simplicity, this cold-weather classic is swirling with science. The backbone of any decent hot chocolate is milk. Beyond water, milk is perhaps the most basic and familiar substance to humans.

7 0

2 years ago

The volume of a sample gas, initially at 25 C and 158 mL, increased to 450 mL. What is the final temperature of the sample of ga

Rashid [163]

Answer:

Final temperature of the gas is 576 $^{0}\textrm{C}$ .

Explanation:

As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:

$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

where $V_{1}$ and $V_{2}$ are volume of gas at $T_{1}$ and $T_{2}$ temperature (in kelvin scale) respectively.

Here $V_{1}=158mL$ , $T_{1}=(273+25)K=298K$ and $V_{2}=450mL$

So $T_{2}=\frac{V_{2}T_{1}}{V_{1}}=\frac{(450mL)\times (298K)}{(158mL)}=849K$

849 K = (849-273) $^{0}\textrm{C}$ = 576 $^{0}\textrm{C}$

So final temperature of the gas is 576 $^{0}\textrm{C}$ .

3 0

3 years ago

How many hours will it take for the concentration of methyl isonitrile to drop to 15.0 % of its initial value?

SpyIntel [72]

Answer:

The concentration of methyl isonitrile will become 15% of the initial value after 10.31 hrs.

Explanation:

As the data the rate constant is not given in this description, However from observing the complete question the rate constant is given as a rate constant of 5.11x10-5s-1 at 472k .

Now the ratio of two concentrations is given as

$ln (\frac{C}{C_0})=-kt$

Here C/C_0 is the ratio of concentration which is given as 15% or 0.15.

k is the rate constant which is given as $5.11 \times 10^{-5} \, s^{-1}$

So time t is given as

$ln (\frac{C}{C_0})=-kt\\ln(0.15)=-5.11 \times 10^{-5} \times t\\t=\frac{ln(0.15)}{-5.11 \times 10^{-5} }\\t=37125.6 s\\t=37125.6/3600 \\t= 10.31 \, hrs$

So the concentration will become 15% of the initial value after 10.31 hrs.

7 0

3 years ago

Read 2 more answers

True or False

goldenfox [79]

Answer:

I believe its True

4 0

3 years ago

Read 2 more answers