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lianna [129]
3 years ago
5

Which would cause a hazard when working with chemicals in laboratory?

Chemistry
1 answer:
Ivanshal [37]3 years ago
6 0
Hey there,
The answer is A, touching a chemical.
You need to wear gloves and safety googles when handling chemicals to prevent any hazards.

Hope this helps :))

<em>~Top♥</em>
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What condition must be met for a battery to be rechargeable?
Neko [114]

Answer:

D. The electrochemical reaction of the battery must be reversible.

Explanation:

The batteries are based on the production of an electric flux given by a<u> redox reaction</u>. This reaction is <u>spontaneous</u> and is<u> thermodynamically favored</u>.

Thus, when the reactants to the reaction are finished, the flow of current stops and ends. Therefore, when current is administered from another source, the reaction <u>changes its direction</u> and reagents that were previously consumed begin to occur. Therefore the condition for it to be <u>rechargeable</u> is that the reaction can go <u>forward or backward</u>, that is, it is <u>reversible</u>.

3 0
3 years ago
Copper conducts heat well.<br> physical<br> chemical
OverLord2011 [107]

Answer:

Physical property

Explanation:

We can visualize the property without the need to do any experiments.

7 0
3 years ago
What are 2 comparisons between organisms and music?
Brrunno [24]

Answer:

Explanation:

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6 0
3 years ago
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A gold coin contains 3.47 × 10^23<br> gold atoms.<br> What is the mass of the coin in grams?
VashaNatasha [74]

Answer:

Mass = 114.26 g

Explanation:

Given data:

Number of gold atoms = 3.47×10²³ atoms

Mass in gram = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

3.47×10²³ atoms × 1 mol  /6.022 × 10²³ atoms

0.58 mol

Mass of gold:

Mass = number of moles × molar mass

Mass = 0.58 mol × 197 g/mol

Mass = 114.26 g

4 0
3 years ago
How many grams of O2(g) are needed to completely burn 15.6 g of C3H8(g)?
alexdok [17]
15.6gC3H8*44.1gC3H8*32gO2=11.32
7 0
3 years ago
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