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zavuch27 [327]
2 years ago
10

What happens if : . The test charge is not tiny.

Physics
1 answer:
docker41 [41]2 years ago
3 0

The magnitude of the test charge must be small enough so that it does not disturb the issuance of the charges whose electric field we wish to measure otherwise the metric field will be different from the actual field.

<h3>How does test charge affect electric field?</h3>

As the quantity of authority on the test charge (q) is increased, the force exerted on it is improved by the same factor. Thus, the ratio of force per charge (F / q) stays the same.

Adjusting the amount of charge on the test charge will not change the electric field force.

<h3>What is a test charge used for?</h3>

The charge that is used to measure the electric field strength is directed to as a test charge since it is used to test the field strength. The test charge has a portion of charge denoted by the symbol q.

To learn more about test charge, refer

brainly.com/question/16737526

#SPJ9

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What is the magnitude of a point charge that would create an electric field of 1.18 N/C at points 0.822 m away?
katrin [286]

Answer:

q = 8.85 x 10⁻¹¹ C

Explanation:

given,

Electric field, E = 1.18 N/C

distance, r = 0.822 m

Charge magnitude = ?

using formula of electric field.

E = \dfrac{kq}{r^2}

k is the coulomb constant

q= \dfrac{Er^2}{k}

q= \dfrac{1.18\times 0.822^2}{9\times 10^9}

  q = 8.85 x 10⁻¹¹ C

The magnitude of charge is equal to q = 8.85 x 10⁻¹¹ C

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3 years ago
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A mango fruit drops from the top of it's tree which is 40 m. How long does it takes to reach the ground
IrinaVladis [17]
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3 years ago
Ferns that eject spores generally do so in pairs, with two spores flying off in opposite directions. The structure from which th
Furkat [3]

Answer:

It cancels recoil.

Explanation:

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4 years ago
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fiasKO [112]
Let's use the mirror equation to solve the problem:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i}
where f is the focal length of the mirror, d_o the distance of the object from the mirror, and d_i the distance of the image from the mirror.
For a concave mirror, for the sign convention f is considered to be positive. So we can solve the equation for d_i by using the numbers given in the text of the problem:
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6 0
3 years ago
Read 2 more answers
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