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Ber [7]
2 years ago
7

Which would most likely cause a decrease in the rate of energy production in a fusion nuclear reactor?

Physics
2 answers:
White raven [17]2 years ago
7 0

Answer:

A: a drop in the temperature in the reactor

Explanation:

right on edg

lesya [120]2 years ago
4 0

In a fusion nuclear reactor, a drop in temperature would most likely result in a decline in the rate of energy output.

<h3 /><h3>What is nuclear power?</h3>

The utilization of nuclear reactions to generate energy is known as a nuclear power. Nuclear fission, nuclear decay, and nuclear fusion processes are all sources of nuclear energy.

Nuclear power facilities currently produce the great bulk of the electricity generated by nuclear fission of uranium and plutonium.

The environment must be hot enough for the deuterium and tritium ions' kinetic energies to be sufficient to break through the Coulomb barrier and fuse together.

Hence a decrease in temperature would most likely cause a decrease in the rate of energy production in a fusion nuclear reactor.

To learn more about nuclear power refer to the link;

brainly.com/question/9859575

#SPJ1

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If the mass of a material is 41 grams and the volume of the material is 5 cm^3, what would the density of the material be? answe
Mila [183]
Density can be calculated using the following rule:
Density = mass/volume

We are given that:
mass = 41 grams
volume = 5 cm^3

Substitute with the givens in the above equation to get the density as follows:
Density = 41/5 = 8.2 g/cm^3

Based on the above calculations:
answer : 8.2
units : g/cm^3
6 0
3 years ago
Read 2 more answers
How much work is needed to push a 117- kg packing crate a distance of 2.75 m up an inclined plane that makes an angle of 28 o wi
Nataly_w [17]

Answer:

W_{tot,min} = 1481.372\,J

Explanation:

The minimum total work is the work needed to counteract the work associated with the weight:

W_{tot, min} = W_{F}

W_{tot,min} = m\cdot g\cdot \sin \theta \cdot \Delta s

W_{tot,min} = (117\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (\sin 28^{\textdegree}) \cdot (2.75\,m)

W_{tot,min} = 1481.372\,J

6 0
3 years ago
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A 0.141 kg pinewood derby car is moving 1.33 m/s . What is its momentum?
kompoz [17]

momentum= mass × velocity = 0.141kg×1.33m/s= 0.18753kg m/s = 0.188kg m/s (3s.f.)

7 0
3 years ago
When operated on a household 110.0 V line, typical hair dryers draw about 1650 W of power. The current can be modeled as a long,
Andre45 [30]

Explanation:

Given that,

Voltage of household line, V = 110 V

Power of the hairdryer, P = 1650 W

During use, the current is about 1.95 cm from the user's hand.

(a) Power is given by :

P=V\times I\\\\I=\dfrac{P}{V}\\\\I=\dfrac{1650\ W}{110\ V}\\\\I=15\ A

(b) Again the power is given by :

P=\dfrac{V^2}{R}

R is resistance of the dryer

R=\dfrac{V^2}{P}\\\\R=\dfrac{(110)^2}{1650}\\\\R=7.34\ \Omega

(c) The magnetic field produced by the dryer at the user's hand is given by :

B=\dfrac{\mu_o I}{2\pi r}\\\\B=\dfrac{4\pi \times 10^{-7}\times 15}{2\pi \times 1.95\times 10^{-2}}\\\\B=1.53\times 10^{-4}\ T

Hence, this is the required solution.

4 0
3 years ago
Please look at the diagram and ans that question
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