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Lana71 [14]
3 years ago
8

Two numbers, a and b, are each greater than zero, and the square root of a is equal to the cube root of b. For what value of x i

s a^(2x-1) equal to b ?
Mathematics
1 answer:
hammer [34]3 years ago
3 0

Answer:

x = 1/2

Step by step explanation:

Two numbers a and b are each greater than zero.

i.e a > 0 and b > 0

And;

\sqrt{a}  \:  =  \:  \sqrt[3]{b}

Since the square root of a is equal to cube root of b then,

a = b = 1

{a}^{2x \:  -  \: 1}  \:  = \: b

{1}^{2x \:  -  \: 1}  = {1}^{0}

2x - 1 = 0

x = 1/2

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