Answer:
Therefore the Area of Rhombus ABCD is 36 unit².
Step-by-step explanation:
Given:
ABCD is a Rhombus
A = (-1,0)
B = (5,-3)
C = (-1,-6)
D = (-7 ,-3)
To Find:
Area of Rhombus ABCD = ?
Solution:
We know that Area of Rhombus is given as
Where ,
d₁ and d₂ are the Diagonals.
We have,
Diagonals as AC and BD,
Using Distance Formula we get
Substituting coordinates A and C we get
Similarly for BD we have,
Now Substituting AC and BD in Formula we get
Therefore the Area of Rhombus ABCD is 36 unit².
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One method is to plot the points P(3,6) and Q(7,3) on the same xy grid. Plot a third point R at (3,3). See the diagram below.
A right triangle forms in which we can find the legs PR = 3 and RQ = 4. The hypotenuse is found through the pythagorean theorem.
a^2+b^2=c^2
3^2+4^2 = c^2
9+16 = c^2
c^2 = 25
c = sqrt(25)
c = 5
This is the length of PQ
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Or you can use the distance formula which is effectively using the pythagorean theorem just in a slightly different format (though it may not be obvious).
