Given :
A certain compound contains 4.0 g of calcium and 7.1 g of chlorine.
Its relative molecular mass is 111.
To Find :
Its empirical and molecular formulas.
Solution :
Moles of calcium ,
.
Moles of chlorine ,
.
The ratio calcium and chlorine is 1 : 2 .
So , the empirical formula is
.
Now , molecular mass of
is :

So , 
Therefore , the molecular formula is also
.
Hence , this is the required solution .
Answer:
An Alkaline solution should be the answer to that.
3.46 g Cu 1 mol Cu 6.02*10^23 atoms Cu =
63.55 g Cu 1 mol Cu
3.28*10^22 atoms Cu
Answer:Noble gases:
are highly reactive.
react only with other gases.
do not appear in the periodic table.
are not very reactive with other elements.
Explanation:Noble gases:
are highly reactive.
react only with other gases.
do not appear in the periodic table.
are not very reactive with other elements.