Answer:
1) Monochrome
2) Monocot
3) Monosaccharide
4) Monounsaturated
5) Monoxide
Explanation:
The prefix mono or mon is of Greek origin and it means single, lone or one.
From the meaning of the words we can tell that they have something in common:
1) Monochrome: This refers to an artwork, a painting or drawing that has just one color.
2) Monocot: This is a type of flowering plant that has a single embryo and a single cotyledon.
3) Monosaccharide: This is a type of simple sugar that contains one sugar unit that cannot be split.
4) Monounsaturated: This refers to a molecule that contains one double or triple bond.
5) Monoxide: This refers to a form of oxide that contains only one oxygen atom.
From the definitions above, all the words mean having only one or a single item.
That is what they have in common.
Answer:
Both are endothermic reactions.
Explanation:
Chemical equation:
1/2H₂(g) + 1/2I₂(g) → HI(g) + 6.2 kcal/mol
Chemical equation:
21.0 kcal/mol + C(s) + 2S(s) → CS₂
Both reaction are endothermic because heat is added in both of reactions.
Endothermic reactions:
The type of reactions in which energy is absorbed are called endothermic reactions.
In this type of reaction energy needed to break the bond are higher than the energy released during bond formation.
For example:
C + H₂O → CO + H₂
ΔH = +131 kj/mol
it can be written as,
C + H₂O + 131 kj/mol → CO + H₂
Exothermic reaction:
The type of reactions in which energy is released are called exothermic reactions.
In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.
For example:
Chemical equation:
C + O₂ → CO₂
ΔH = -393 Kj/mol
it can be written as,
C + O₂ → CO₂ + 393 Kj/mol
Answer:
Explanation:
Hello,
In this case, we can study the ideal gas equation that relates temperature, volume, pressure and moles as shown below:
Thus, since we are asked to compute the pressure y simply solve for it as follows:
Best regards.
Answer:
Check explanation
Explanation:.
NOTE: kindly check for attached file/picture for the graph.
From the graph of absorbance against concentration from the question. We can see that the 0.3 mark absorbance is equivalent to 0.15 M. So, the concentration of CuSO4 is 0.15 M.
The concentration can also be calculated using the Beer-lambert equation for absorbance. The equation is given below;
A= ɛ×C×l --------------------------------------------------------------------------------------(1).
Where A= absorbance, ɛ= molar absorptivity, C= concentration and l= length.
Therefore, the concentration,C will now be; C= A/ ɛ×l. -------------------------------------------------------------------------(2).
Assuming the length,l is 1cm.
Hence, C= 0.300/ ɛ×1.
C= (0.300/ ɛ) M.
