Answer: 2.744 x 1025 molecules
The balanced reaction is 2KClO3 --> 2KCl + 3O2
We first divide the 400.0 g KClO3 by the molar mass of 122.55 g/mol to get 3.26 mol KClO3. Next, we use the coefficients: 3.26 mol KClO3 * (3 mol O2 / 2 mol KClO3) = 4.896 mol O2. Multiplying this by the molar mass of 32 g/mol gives 156.67 g O2.
Percent yield = 115.0 g / 156.67 g = 0.734 = 73.40%
Answer:
196 gdm-3
Explanation:
There are two major units of concentration, moldm-3 and gdm-3. The first unit refers to molar concentration while the second unit refers to mass concentration. Both units are useful in chemistry when describing the concentration of solutions as deemed expedient in each particular case.
Here we are required to compute the mass concentration from the molar concentration. We must recall that; mass concentration= molar concentration × molar mass
Let us first obtain the molar mass of H2SO4 from the relative atomic masses given=
2(1) + 32 + 4(16) = 98 gmol-1
Molar concentration of H2SO4 = 2 moldm-3
Mass concentration= 2 moldm-3 × 98 gmol-1
Mass concentration = 196 gdm-3
