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frosja888 [35]
3 years ago
6

Escribo dentro del paréntesis la letra (F) si el enunciado es falso o (V) si el enunciado es verdadero. Fundamento si mi elecció

n es falsa a. () La resistencia es una cualidad que nos permite soportar esfuerzos prolongados b. ( ) Existen dos tipos de resistencia láctica y la aláctica C ( En la resistencia aeróbica intervienen los sistemas respiratorio y el circulatorio d ( > En la resistencia aeróbica se trabaja con déficit de oxigeno La resistencia anaeróbica nos permite soportar esfuerzos de larga duración Cito los beneficios de la resistencia aérobica y la anaeróbica a. Resistencia aeróbica b. Resistencia anaeróbica
Physics
1 answer:
KatRina [158]3 years ago
4 0

Answer:

El primero es (V) y el segundo es(f)

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7. A double-slit experiment uses coherent light of wavelength 633 nm with a slit separation of 0.100 mm and a screen placed 2.0
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Answer:

The distance between first-order and second-order bright fringes is 12.66mm.

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The physicist Thomas Young establishes through its double slit experiment a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.

\Lambda x = L\frac{\lambda}{d}  (1)

Where \Lambda x is the distance between two adjacent maxima, L is the distance of the screen from the slits, \lambda is the wavelength and d is the separation between the slits.  

The values for this particular case are:

L = 2.0m

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Notice that is necessary to express L and \lambda in units of milimeters.

L = 2.0m \cdot \frac{1000mm}{1m} ⇒ 2000mm

\lambda = 633nm \cdot \frac{1mm}{1x10^{6}nm} ⇒ 6.33x10^{-4}mm

Finally, equation 1 can be used:

\Lambda x = (2000mm)\frac{(6.33x10^{-4}mm)}{(0.100mm)}

\Lambda x = 12.66mm

Hence, the distance between first-order and second-order bright fringes is 12.66mm.

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