2 years ago

(03.04 MC)

Physics

1 answer:

weqwewe [10]2 years ago

4 0

Answer:

1/4

Explanation:

If the distance between two charges is doubled, the attraction of repulsion between the two becomes weaker, and decreases to 1/4 of the original value.

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<h3>Height of the bullet when the velocity is zero </h3>

The height of the bullet when the velocity is zero is determined by taking derivative of the function as shown below;

$v = \frac{dy}{dt} = 128 -32t \\\\when \ v \ is \ zero\\\\v = 0\\\\128 - 32t = 0\\\\32t = 128\\\\t = \frac{128}{32} \\\\t = 4 \ s$

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Learn more about height of projectiles here: brainly.com/question/10008919

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