We are given the function:
g(x) = 6 (4)^x
Part A.
To get the average rate of change, we use the formula:
average rate of change = [g(x2) – g(x1)] / (x2 – x1)
Section A:
average rate of change = [6 (4)^1 – 6 (4)^0] / (1 – 0) =
18
Section B:
average rate of change = [6 (4)^3 – 6 (4)^2] / (3 – 2) =
288
Part B.
288 / 18 = 16
Therefore the average rate of change of Section B is 16 times
greater than in Section A.
<span>The average rate of change is greater between x = 2 to x = 3 than between
x = 1 and x = 0 because an exponential function's rate of change increases
with increasing x (not constant).</span>
.75 is the answer because it looks like division
Answer:
17/13
Step-by-step explanation:

Answer:
a. False
b. True
Step-by-step explanation:
Given that:
The sample size of the college student n = 100
The population of student that participated p = 38
We are to identify from the following statement if it is true or false.
From part a;
It is false since the random samples not indicate the population perfectly. As such we can't conclude that the proportion of students at this college who participate in intramural sports is 0.38.
The statement in part b is true because the sampling variation, random samples also do not indicate the population perfectly but it is close to be 0.38. Thus, it is suitable to conclude that the proportion of students at this college who participate in intramural sports is likely to be close to 0.38, but not equal to 0.38.
Answer:
3x=x+30
2x=30
x=15
3(15)=45
15+30=45
45 for both
hope that answers your question
Step-by-step explanation: