Question

Help me plzzzz!!!!!!!!!!!!!

Answer 1

Answer:

Perpendicular line is 7y = x - 26

Parallel line is y = -7x - 32

Step-by-step explanation:

» For the perpendicular line:

from line: y = -7x + 3

m1 is -7

gradient for needed line:

$m_{1} \times m_{2} = - 1 \\ - 7m_{2} = - 1 \\ m_{2} = \frac{1}{7}$

for y-intercept, at point (-2, -4):

$y = mx + c \\ - 4 = ( - 2 \times \frac{1}{7} ) + c \\ \\ c = - 4 + \frac{2}{7} \\ \\ c = - \frac{26}{7}$

equation:

$y = \frac{1}{7} x - \frac{26}{7} \\ \\ { \underline{7y = x - 26}}$

» For parallel line:

gradients are the same, m = -7

for y-intercept, at (-2, -4):

$y = mx + c \\ - 4 = ( - 2 \times - 7) + c \\ c = - 4 - 28 \\ c = - 32$

${ \underline{y = - 7x - 32}}$