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mote1985 [20]
3 years ago
12

What year did niels bohr discover the atomic theory​

Physics
2 answers:
Ludmilka [50]3 years ago
8 0

Answer:

1913

Explanation:

<u>A hypothesis of the hydrogen atom was developed by Niels Bohr in 1913, based on the quantum theory</u>, which states that certain physical quantities can only have discrete values. Electronic particles travel about a nucleus, but only in specified orbits. If electrons jump to a lower-energy orbit, the energy difference between the two orbits is emitted as radiation.

Hope this helps explain what the answer to your question is and why it is that answer.

Dimas [21]3 years ago
7 0

Answer:

1913

Explanation:

In 1913, Niels Bohr proposed a theory for the hydrogen atom, based on quantum theory that some physical quantities only take discrete values. Electrons move around a nucleus, but only in prescribed orbits, and If electrons jump to a lower-energy orbit, the difference is sent out as radiation.

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According to the text, there is no energy shortage now, nor will there ever be. what reason (s) is given to support this stateme
Bas_tet [7]
The reason why there is no energy shortage nor will there ever be is because energy is being preserved and conserved and only changes form. It never gets lost or increased.
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What is the mass of a baseball thrown at 25 m/s resulting in a momentum
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250kg

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3 years ago
Which of the following is not a symptom associated with hypertension
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Do you have any answer choices?

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3 years ago
4. Marcia consumes 8.4 X 10.J (2000 food calories) of energy per day while maintaining a constant weight.
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Explanation:

5 0
3 years ago
The 30-kg disk is originally spinning at v = 125 rad&gt;s. If it is placed on the ground, for which the coefficient of kinetic f
irga5000 [103]

Answer:

t = 3.82 s

Ax = 147 N  (←)

Ay = 294 N   (+↑)

Explanation:

Given

m = 30.0 Kg

ωinitial = 125 rad/s

ωfinal = 0 rad/s

μC = 0.5

R = 0.3 m

t = ?

Ax = ?

Ay = ?

For the disk, we can apply

∑ τ = I*α

where I = m*R²/2

then

⇒ R*Ffriction = (m*R²/2)*α

⇒ R*(-μC*N) = R*(-μC*m*g) = (m*R²/2)*α

⇒ α = -2*μC*g / R

⇒ α = -2*(0.5)*(9.8) / 0.3 = -32.666 rad/s²

we can use the equation to get t:

α = Δω / t      ⇒   t = Δω / α = (0 - 125) / (-32.666)

⇒   t = 3.82 s

The horizontal and vertical components of force which the member AB exerts on the pin at A during this time are

∑ Fx = 0  (+→)

Ax - Ffriction = 0

⇒  Ax = Ffriction = μC*m*g = (0.5)*(30)*(9.8) = 147 N

⇒   Ax = 147 N  (←)

∑ Fy = 0   (+↑)

⇒  Ay - m*g = 0

⇒  Ay = m*g

⇒  Ay = 30*9.8 = 294 N

⇒  Ay = 294 N   (+↑)

5 0
3 years ago
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