Answer: B
Explanation:
Displacement is a vector quantity. it is the distance covered in a specific direction.
Whereas, Velocity = displacement/time
Make displacement the subject of formula
Displacement = velocity × time
From the graph, velocity is constant which is equal to 1 m/s
Displacement in the last two seconds will be velocity multiply by 2. Since time = 2s. Therefore,
Displacement = 1 × 2 = 2 m
So, the particle displacement in the last two seconds will be 2 metres
It is rectangle and it probably is a lake perhaps
Answer:
1.11
Explanation:
The index of the medium can be calculated using below formula
V= c/ n ............eqn(1)
Where V= velocity of the light is reduced to while traveling through the second medium= 2.7 x 10^8 m/s
n= index of the medium
c= speed of light= 3 x 10^8 m/s
Substitute for the values in eqn(1)
2.7 x 10^8 = (3 x 10^8 m/s)/ n
Making " n" subject of the formula, we have
n= (3 x 10^8 )/(2.7 x 10^8)
n= 1.11
Hence, the index of the medium is 1.11
Given:
u = 6.5 m/s, initial velocity
a = 1.5 m/s², acceleration
s = 100.0 m, displacement
Let v = the velocity attained after the 100 m displacement.
Use the formula
v² = u² + 2as
v² = (6.5 m/s)² + 2*(1.5 m/s²)*(100 m) = 342.25 (m/s)²
v = 18.5 m/s
Answer: 18.5 m/s
