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suter [353]
3 years ago
11

A bat hits a moving baseball. If the bat delivers a net eastward impulse of 0.80 N-s and the ball starts with an initial horizon

tal velocity of 3.8 m/s to the west and leaves with a 5.7 m/s velocity to the east, what is the mass of the ball (in grams)? (NEVER include units in the answer to a numerical question.)
Physics
1 answer:
AURORKA [14]3 years ago
8 0

Answer:

0.084 kg

Explanation:

I = 0.80 N-s (East wards) = 0.80 i N-s

u = 3.8 m/s = - 3.8 i m/s

v = 5.7 m/s = 5.7 i m/s

Let m be the mass of bat.

I = m (v - u)

0.8 i = m ( 5.7 i + 3.8 i)

0.8 i = m x 9.5 i

m = 0.084 kg

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Winds tend to rotate in a counter clockwise direction in the ___ (northern or southern) Hemisphere as they move into a low press
lana [24]

Answer:

Winds tend to rotate in a counter clockwise direction in the center of northern and southern hemisphere.

Explanation:

The wind blows clockwise around a high pressure area  in the northern hemisphere and the wind blows counter - clockwise around low pressure.  

In the northern hemisphere High-pressure systems rotate clockwise direction and in the southern hemisphere  low-pressure systems rotate clockwise direction.

 

8 0
3 years ago
Read 2 more answers
A heat engine accepts 200,000 Btu of heat from a source at 1500 R and rejects 100,000 Btu of heat to a sink at 600 R. Calculate
diamong [38]

To solve the problem it is necessary to apply the concepts related to the conservation of energy through the heat transferred and the work done, as well as through the calculation of entropy due to heat and temperatra.

By definition we know that the change in entropy is given by

\Delta S = \frac{Q}{T}

Where,

Q = Heat transfer

T = Temperature

On the other hand we know that by conserving energy the work done in a system is equal to the change in heat transferred, that is

W = Q_{source}-Q_{sink}

According to the data given we have to,

Q_{source} = 200000Btu

T_{source} = 1500R

Q_{sink} = 100000Btu

T_{sink} = 600R

PART A) The total change in entropy, would be given by the changes that exist in the source and sink, that is

\Delta S_{sink} = \frac{Q_{sink}}{T_{sink}}

\Delta S_{sink} = \frac{100000}{600}

\Delta S_{sink} = 166.67Btu/R

On the other hand,

\Delta S_{source} = \frac{Q_{source}}{T_{source}}

\Delta S_{source} = \frac{-200000}{1500}

\Delta S_{source} = -133.33Btu/R

The total change of entropy would be,

S = \Delta S_{source}+\Delta S_{sink}

S = -133.33+166.67

S = 33.34Btu/R

Since S\neq   0 the heat engine is not reversible.

PART B)

Work done by heat engine is given by

W=Q_{source}-Q_{sink}

W = 200000-100000

W = 100000 Btu

Therefore the work in the system is 100000Btu

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3 years ago
Where does most of the energy we use at home/our cars come from?
KengaRu [80]
It comes from the sun, and then it is converted to energy/electricity (by solar panels)
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A baseball thrown from the outfield to home plate does not have which of the following types of energy while it's in the air? A.
posledela
The ball does not have D. Radiant energy.
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A truck’s engine produces 20,000 N of force. It dumps its load and its mass is reduced to 10,000 kg. What is the acceleration of
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Explanation:

If F = m*a, we can easily solve for a.

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