Question

Write the equation in vertex form that has the root of -7 and has a vertex of (-1,-9)

Answer 1

Answer:

$y=\frac{1}{4}(x+1)^2-9$

Step-by-step explanation:

Method 1

we know that

The equation of a vertical parabola in vertex form is equal to

$y=a(x-h)^2+k$

where

a is the leading coefficient

(h,k) is the vertex

we have

(h,k)=(-1,-9)

substitute

$y=a(x+1)^2-9$

Remember that

one root is (-7,0)

substitute and solve for a

$0=a(-7+1)^2-9$

$0=a(-6)^2-9$

$0=36a-9$

$a=\frac{1}{4}$

therefore

$y=\frac{1}{4}(x+1)^2-9$

Method 2

I use the fact that the roots are the same distance from the vertex

the distance from the given root to the vertex is equal to

6 units

so

If one root is x=-7

then the other root is

x=-1+6=5

The general equation of the quadratic equation is equal to

$y=a(x+7)(x-5)$

we have the vertex (-1,-9)

substitute the value of x and the value of y and solve for a

$-9=a(-1+7)(-1-5)$

$-9=a(6)(-6)$

$-9=-36a$

$a=\frac{1}{4}$

$y=\frac{1}{4}(x+7)(x-5)$

so

Expanded the equation, complete the square and rewrite as vertex form