100 m = 0.1 km
9.58 sec = 9.58/3600 = 0.00266 hr
Speed = 0.1/0.00266= 37.6 km/hr
Can you mark it brainliest?
Answer:
![pH=6.07 .](https://tex.z-dn.net/?f=pH%3D6.07%20.)
Explanation:
It is given that pH of
.
Now, molality of
, M=![\dfrac{No\ of\ moles}{Volume\ in\ liters}=\dfrac{4}{2}=2\ molar.](https://tex.z-dn.net/?f=%5Cdfrac%7BNo%5C%20of%5C%20moles%7D%7BVolume%5C%20in%5C%20liters%7D%3D%5Cdfrac%7B4%7D%7B2%7D%3D2%5C%20molar.)
Now, we know,
...1
Here C is concentration.
Now, ![pK_a=-logK_a=-log(4.3\times 10^-7)=6.37 .](https://tex.z-dn.net/?f=pK_a%3D-logK_a%3D-log%284.3%5Ctimes%2010%5E-7%29%3D6.37%20.)
Putting all values in equation 1.
We get,
![pH=6.37-0.30=6.07 .](https://tex.z-dn.net/?f=pH%3D6.37-0.30%3D6.07%20.)
Hence, this is the required solution.
To answer the question that is: "which factors affect a river's load", we have to understand that all the things mentioned are important. All these options (river's slope, streambed shape and volume of flow) affect the amount of energy that the river has to spend and the way the river spend that energy, so, it is right to mark the alternative <span>d) all of the above.</span>
Answer:
The final temperature (in degrees Celsius) of the iron block is 85.82 °C
Explanation:
<u>Determine the heat emitted by the condensing water.</u>
qw = 0.88 g H2O
![\frac{- 44 kJ}{1 mol H2O}](https://tex.z-dn.net/?f=%5Cfrac%7B-%2044%20kJ%7D%7B1%20mol%20H2O%7D)
qw = -2.1492 kJ
<u>Determine the heat absorbed by the iron block</u>
qw = - qw = - (-2.1492 kJ) = 2.1492 kJ
<u>Look up the specific heat for iron. Use the specific heat equation to solve for the final temperature of the iron block.</u>
q = mcΔT
ΔT = q / mc
Temp f = (q / mc) + Temp i
Temp f = 2.1492 x 10^3 J / 75 g (0.449 J/g.°C) + 22 °C
Temp f = 85.82 °C
Answer:
1.7
Explanation:
4.52/2.6 = 1.738461538, which can be simplified to 1.7