Given that log 2-0.3010, find the value of log 1/6
1 answer:
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Answer:
mFG = 67r ( Where r is the radius of the circle)
∠ECF = 67°
Step-by-step explanation:
i) m FG
Join CG
∠GCF=67°
(As FG=ED and equal chords subtend equal angle at center)
Now The length of the minor arc is given by the formula
m arc FG =
∠C=67
m arc FG =
m arc FG = 67r
Where r is the radius of the circle.
2. ∠ECF = 67°
It is because of the rule which says that equal chords subtend equal angle at center
DE = EF
Hence ∠DCE = ∠ECF