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quester [9]
3 years ago
11

A car moves with uniform velocity of 40m/s for 5 s. It comes to rest in the next 10 s with uniform deceleration

Physics
1 answer:
timama [110]3 years ago
3 0

Answer:

-8 m/s²

Explanation:

Initial velocity = 40 m/s

Final velocity = 0 m/s

Time (T1) = 5 s

Time (T2) = 10 s

Acceleration = v - u/t2 - t1

Acceleration = 0 - 40/10 - 5

Acceleration = -40/5

Acceleration = -8 m/s²

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Which of the following is least likely to be a scientific experiment?
nikitadnepr [17]
D should be the answer
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3 years ago
A radioactive element undergoes decay via the loss of two alpha particles to form a stable daughter isotope. Following the decay
jeyben [28]

Answer:

Atomic number of the daughter isotope = (Atomic number of the parent isotope) - 4

Explanation:

An alpha particle has atomic number of 2 and a mass number of 4

Losing two alpha particles would lead to a reduction of 4 in atomic number and 8 in mass number for the radioactive isotope, to give the stable daughter isotope.

8 0
3 years ago
Calculate the work performed by an ideal Carnot engine as a cold brick warms from 150 K to the temperature of the environment, w
olga nikolaevna [1]

To solve this problem, apply the concepts related to the calculation of the work performed according to the temperature change (in an ideal Carnot cycle), for which you have to:

W = \int\limit_{T_c}^{T_H} C (1-\frac{T_H}{T})

Where,

C = Heat capacity of the Brick

T_C= Cold Temperature

T_H = Hot Temperature

Integrating,

W = C (T_H-T_C)- T_H C ln (\frac{T_H}{T_C})

Our values are given as

T_H= 300K

T_C = 150K

Replacing,

W = (1) (300-150)-300(1)ln(2)

W = 150-300ln2

W = -57.94kJ \approx 58kJ

Therefore the work perfomed by this ideal carnot engine is 58kJ

5 0
4 years ago
Please need help this
snow_tiger [21]
Melting and pressure.

Weathering and erosion affect any surface rock and make sedimentary rocks, heat and pressure make metamorphic rocks, and melting and cooling make igneous rocks. Melting and pressure is not a step.
8 0
3 years ago
The current theory of the structure of the
irina1246 [14]

Answer:

pt 1: m=1.66698*10^{21} kg

Pt 2: KE=1212.23531 J

Explanation:

Information Given: (p = density)

l = 5200km  d = 35km p = 2700kg/m^{2}

Part 1: Mass

  • Find volume
  1. V=(l)^2(d)
  2. V=(4.2*10^6)^2(35*10^3)
  3. V=61.74*10^{16}
  • Find Mass
  1. m=Vp
  2. m=(61.74*10^{16})(2700)
  3. m=1.66698*10^{21}

Part 2: Kinetic Energy

  1. v=\frac{3.8cm}{yr}*\frac{m}{100cm}*\frac{yr}{365d}*\frac{d}{24hr}*\frac{hr}{3600s}
  2. v=1.20497*10^{-9}

KE=\frac{1}{2}mv^2

KE=\frac{1}{2} (1.66698*10^{21})(1.20497*10^{-9})^2

KE=1212.23531 J

Part 3: Jogger Speed

set up, because I don't have the mass :(

Information given:

KE_{jogger}

  1. KE=\frac{1}{2}mv^2
  2. v_{jogger} =\sqrt{\frac{2KE}{m_{jogger} } }
  • Input the values

Hope it helps :)

6 0
3 years ago
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