Answer:
Heat Capacity = E / T.
- Find the difference in temperature for changes of multiple degrees.
- Add the appropriate units to your answer to give it meaning.
- Know that this equation works for cooling objects as well.
- Know that specific heat refers to the energy needed to raise one gram by one degree.
Given that,
Puck slide total Deltax = 12m
Puck and board Mk = 0.10
Find the initial speed = ?
We know that,
Vf^2-Vi^2 = 2a Deltax
-Vi^2 = -2MkgDeltax ............(1)
then,
fk = -Mk mg = ma
a = -Mkg .........(2)
From equation (1),
Vi^2 = 2MkgDeltax
Vi = âš2MkgDeltax [g=9.8m/s^2]
Vi = âš2(0.10)(0.98)(12)
Vi = âš0.2(9.8)(12)
Vi = âš1.92(12)
Vi = âš23.52
Vi = 4.8 m/s
Therefore the initial speed of the puck Vi = 4.8 m/s
The distance between the two charges is 
Explanation:
The electrostatic force between two charged objects is given by Coulomb's law:
where:
is the Coulomb's constant
are the charges of the two objects
r is the separation between the two charges
In this problem, we are given the following:
Therefore, we can rearrange the equation to solve for r, the distance between the two charges:
Learn more about electrostatic force:
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Answer:
a) Posición y velocidad después de los 6s
i) Posición = -26.58m
ii) velocidad = -33.86m/s
b) Tiempo para alcanzar la altura máxima
= 2.55s
c) Alcance horizontal
= 220.7m
Explanation:
a) Posición y velocidad después de los 6s
i) Posición
y = (usinθ)t – 1/2 gt²
u = 50m/s
θ = 30°
g = 9.81m/s²
t = 6s
y = (50 × sin 30)6 - 1/2 × 9.81 × 6²
y = 150 - 176.58
y = -26.58m
ii) velocidad
v = u sinθ–gt
u = 50m/s
θ = 30°
g = 9.81m/s²
t = 6s
v = 50 × sin 30 - 9.81 × 6
v = 25 - 58.86
v = -33.86m/s
b) Tiempo para alcanzar la altura máxima
usinθ /g
u = 50m/s
θ = 30°
g = 9.81m/s²
= 50 × sin 30/ 9.81
= 25/9.81
= 2.5484199796s
≈ 2.55s
c) Alcance horizontal
R = u²sin2θ/g
u = 50m/s
θ = 30°
g = 9.81m/s²
R = 50² ×( sin 2 ×30°) /9.81
R = 220.69964419m
≈ 220.7m
