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Butoxors [25]
3 years ago
11

Compare the two numbers using <, >, =

Physics
1 answer:
Effectus [21]3 years ago
3 0
Vas happenin!!

1. =
2. >
3. <
4. <
5. <
6. >

Hope this helps *smiles*

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Which of these statements best explains why it is difficult to see outside at night?
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B is the awser 
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Como se dice casa en náhuatl​
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Chāntli

Explanation:

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A cheetah is known to be the fastest mammal on Earth, at least for short runs. Cheetahs have been observed running a distance of
Arlecino [84]

The cheetah needs 197.8 seconds to complete the 5.50 *100 m distance.

The distance traveled divided by the time taken is the most popular formula for calculating average speed. The average speed is determined by dividing the whole distance by the total time required to complete the distance. The other calculation, provided you have the initial and final speeds, adds them together and divides by 2.20. calculating the time needed for a cheetah to travel 5.50 102 meters.

10 km/h average speed is equal to 10 / 3.6, or 2.78 m/s.

Dist. = 5.50 102

Time =?

average speed = time / distance

time=5.50 x 100/ 2.78

Time = 197.8 s

Therefore, it takes a cheetah 197.8 seconds to travel 5.50 102 meters.

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4 0
1 year ago
Convert 300mil per hr to km per hr​
Dominik [7]

Answer: 482.8032 km per hr

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3 0
3 years ago
A 12.0-g sample of carbon from living matter decays at the rate of 162.5 decays/minute due to the radioactive 14C in it. What wi
Ghella [55]

Answer:

a)143.8 decays/minute

b)0.41 decays/minute

Explanation:

From;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/2=half-life of C-14= 5670 years

t= time taken to decay

Ao= activity of a living sample

A= activity of the sample under study

a)

0.693/5670 = 2.303/1000 log(162.5/A)

1.22×10^-4 = 2.303×10^-3 log(162.5/A)

1.22×10^-4/2.303×10^-3 = log(162.5/A)

0.53 × 10^-1 = log(162.5/A)

5.3 × 10^-2 = log(162.5/A)

162.5/A = Antilog (5.3 × 10^-2 )

A= 162.5/1.13

A= 143.8 decays/minute

b)

0.693/5670 = 2.303/50000 log(162.5/A)

1.22×10^-4 = 4.61×10^-5 log(162.5/A)

1.22×10^-4/4.61×10^-5 = log(162.5/A)

0.26 × 10^1 = log(162.5/A)

2.6= log(162.5/A)

162.5/A = Antilog (2.6 )

A= 162.5/398.1

A= 0.41 decays/minute

4 0
3 years ago
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