B is the awser
good luck and hope it helps
The cheetah needs 197.8 seconds to complete the 5.50 *100 m distance.
The distance traveled divided by the time taken is the most popular formula for calculating average speed. The average speed is determined by dividing the whole distance by the total time required to complete the distance. The other calculation, provided you have the initial and final speeds, adds them together and divides by 2.20. calculating the time needed for a cheetah to travel 5.50 102 meters.
10 km/h average speed is equal to 10 / 3.6, or 2.78 m/s.
Dist. = 5.50 102
Time =?
average speed = time / distance
time=5.50 x 100/ 2.78
Time = 197.8 s
Therefore, it takes a cheetah 197.8 seconds to travel 5.50 102 meters.
Learn more about average speed here-
brainly.com/question/12322912
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Answer: 482.8032 km per hr
Explanation: 300 * 1.609344 =
Answer:
a)143.8 decays/minute
b)0.41 decays/minute
Explanation:
From;
0.693/t1/2 = 2.303/t log (Ao/A)
Where;
t1/2=half-life of C-14= 5670 years
t= time taken to decay
Ao= activity of a living sample
A= activity of the sample under study
a)
0.693/5670 = 2.303/1000 log(162.5/A)
1.22×10^-4 = 2.303×10^-3 log(162.5/A)
1.22×10^-4/2.303×10^-3 = log(162.5/A)
0.53 × 10^-1 = log(162.5/A)
5.3 × 10^-2 = log(162.5/A)
162.5/A = Antilog (5.3 × 10^-2 )
A= 162.5/1.13
A= 143.8 decays/minute
b)
0.693/5670 = 2.303/50000 log(162.5/A)
1.22×10^-4 = 4.61×10^-5 log(162.5/A)
1.22×10^-4/4.61×10^-5 = log(162.5/A)
0.26 × 10^1 = log(162.5/A)
2.6= log(162.5/A)
162.5/A = Antilog (2.6 )
A= 162.5/398.1
A= 0.41 decays/minute
