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avanturin [10]
3 years ago
8

Which of these statements best explains why it is difficult to see outside at night?

Physics
2 answers:
xeze [42]3 years ago
7 0

Answer:

the answer is b

Explanation:

anyanavicka [17]3 years ago
4 0
B is the awser 
good luck and hope it helps 
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A 700 kg racecar slowed from 30 m/s to 15 m/s. What was the change in momentum?
xxMikexx [17]
Momentum equation is

change in momentum = mass•initial velocity•final velocity

so....

p=700(15) because your initial is 30, and your final in 15, so you subtract! hope that helped!
8 0
3 years ago
A young girl gives her toboggan a push of 4.0m/s uphill. It slides up the hill slowing down at an acceleration of 8.0m/s down. I
vivado [14]
It takes 30 seconds for the whole journey
5 0
3 years ago
A service elevator takes a load of garbage, mass 10.0 kg, from a floor of a skyscraper under construction, down to ground level,
kobusy [5.1K]

Answer:

The magnitude of the force the garbage exerts on the floor of the service elevator is 12 N

Explanation:

Given;

mass of the garbage, m = 10.0 kg

acceleration of the elevator, a = 1.2 m/s²

The magnitude of the force the garbage exerts on the floor of the service elevator is given by;

F = ma

F = 10 x 1.2

F = 12 N

Therefore, the magnitude of the force the garbage exerts on the floor of the service elevator is 12 N

8 0
4 years ago
A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. How long until the cannonba
Naddik [55]

Answer:

96.7 s

Explanation:

Time of flight in projectile can be calculated thus:

T = 2 × u × sin ϴ/ g

Where;

T = time of flight (s)

u = initial velocity (m/s)

ϴ = Angle of projectile (°)

g = acceleration due to gravity (9.8m/s²)

Based on the provided information; u = 670m/s, ϴ = 45°

Hence, using T = 2.u.sin ϴ/ g

T = 2 × 670 × sin 45° ÷ 9.8

T = 1340 × 0.7071 ÷ 9.8

T = 947.52 ÷ 9.8

T = 96.68

T = 96.7s

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3 years ago
A 2.0 cm thick brass plate (k_r = 105 W/K-m) is sealed to a glass sheet (kg = 0.80 W/K m), and both have the same area. The expo
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