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juin [17]
3 years ago
15

Find the H.C.F of x² - 3x ,x² - 9​

Mathematics
2 answers:
krek1111 [17]3 years ago
7 0
X^2-3x = x(x-3)
x^2-9 = x^2 - 3^2 = (x-3)(x+3)
HCF = x-3
iris [78.8K]3 years ago
4 0
X²-3x=x(x-3)
x²-9=x²-3²=(x-3)(x+3)
∴the highest common factor of x²-3x and x²-9 is x-3

Hope my answer helped u :)
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Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. Only 1 try
vagabundo [1.1K]

Using the shell method, the volume is

\displaystyle 2\pi \int_0^1 (2-x) \cdot 8x^3 \, dx = 16\pi \int_0^1 (2x^3 - x^4) \, dx

Each cylindrical shell has radius 2-x (the horizontal distance from the axis of revolution to the curve y=8x^3); has height 8x^3 (the vertical distance between a point on the x-axis in 0\le x\le1 and the curve y=8x^3).

Compute the integral.

\displaystyle 16 \pi \int_0^1 (2x^3 - x^4) \, dx = 16\pi \left(\frac{x^4}2 - \frac{x^5}5\right) \bigg|_{x=0}^{x=1} \\\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = 16\pi \left(\frac12 - \frac15\right) \\\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = \frac{24}5\pi = \boxed{4.8\pi}

6 0
1 year ago
Evaluate a+b for a =34 and b=-6
Digiron [165]

Question

evaluate a+b for a =34 and b=-6

a + b =

34 + (-6) =

34 - 6 =

28

5 0
3 years ago
Read 2 more answers
Please I need help ASAP
Goshia [24]

Answer:

It is 300 cubic inches!

Step-by-step explanation:

Im sorry I dont really know how to explain it but- am I correct? ;-;

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3 years ago
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Jamal stands on a dock 1.5 meters above the surface of the water. A trout swims 4.8 meters below Jamal. What is the vertical dis
baherus [9]

Answer:

The correct answer is 4.8 meters.

Step-by-step explanation:

Jamal stands on a dock 1.5 meters above the surface of the water.

A trout swims 4.8 meters below Jamal.

The trout must be swimming below the surface of water.

Therefore the distance below the surface of water where the trout is swimming is 4.8 - 1.5 = 3.5 meters.

But the vertical distance between Jamal and the trout is 4.8 meters only.

5 0
3 years ago
An equation of the line that passes through the given point and is parallel to the graph of the given equation
notsponge [240]

To construct the equations for these lines, we are going to use the point-slope formula, which is:

(y - y_1) = m(x - x_1)

  • m is the slope of the line
  • (x_1, y_1) is a point on the line

1)

In this case, our point is (2, -1) and our line has a slope of 5. (Remember that the line is parallel, meaning that it has the same slope as the given line. Since the line is in the y = mx + b format, we could easily pick out the slope m as being 5.)

Thus, we can "plug in" what we know into our formula to find the equation of our line:

(y + 1) = 5(x - 2)

(y + 1) = 5x - 10

y = 5x - 11


2)

We are going to do the same thing, except our point is now (0, -5) and our slope is now 9.

(y + 5) = 9(x - 0)

y = 9x - 5


Our equations are:

1) y = 5x - 11

2) y = 9x - 5

7 0
3 years ago
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