Answer:
at least three are dimes
so we have 20 coins with a total of 3.50
if the rest are all quarters then there would be 4*3+2=14 but we need 20
so we are 6 short
we must have dimes in multiples of 5
12 q + 5 d=3.50 but only 17 coins
10q +10 dimes=3.50 with 20 coins
10 q +13 dimes total
algebraic solution
d+q=23
25q+10d=380
d=23-q
Step-by-step explanation:
plug the coordinate points into the equations and solve for the remaining variable.
b) (2,3) - 5(2) + b(3) = 16
10 + 3b = 16. 3b= 6. b = 2
(0,8) - 5(0) + 2(8) = 16. 0+ 16 = 16. ☆
a) (4,4) assume based on results you meant y squared. (y^2)
(4)^2 = 4k. 16 = 4k. k = 4
(8)^2 = 4(16). 64 = 64. ☆
Answer:
x + y = - 3
Step-by-step explanation:
The equation for standard form is Ax + By = C. Since there is an invisible 1 in front of both x and y, you can easily solve the problem by subtracting -1x from both sides to get 1x + 1y = -3 or x + y = -3
A. 356.72
always look from the left to right to compare numbers.
Answer:
An integer is a whole number (not a fractional number) that can be positive, negative, or zero. Examples of integers are: -5, 1, 5, 8, 97, and 3,043. Examples of numbers that are not integers are: -1.43, 1 3/4, 3.14, . 09, and 5,643.1.
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