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tiny-mole [99]
3 years ago
5

Câu 15: Khử hỗn hợp X gồm CuO, FeO bằng khí CO sau một thời gian thu được 14,4 gam hỗn hợp rắn A (4 chất) và thoát ra 3,36 lít (

đktc) khí B có tỷ khối so với H2 bằng 18. Hòa tan hoàn toàn A trong dung dịch H2SO4 đặc, nóng dư đến khi phản ứng kết thúc thu được 2,24 lít SO2 (đktc) và dung dịch B. a) Viết các phương trình phản ứng. b) Tính khối lượng mỗi oxit FeO, CuO trong hỗn hợp đầu. c) Cô cạn dung dịch B thu được bao nhiêu gam muối khan.
Chemistry
2 answers:
Vesna [10]3 years ago
7 0

Answer:

hopefully Jennifer Yi bobbin

Nuetrik [128]3 years ago
3 0

Answer:

Cô cạn dung dịch B thu được bao nhiêu gam muối khan.

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Which electron configuration represents the element carbon (atomic number 6)?
trapecia [35]
1s2 2s2 2p2 i hope this helps
5 0
3 years ago
How do the products of chemical reactions compare to their reactants?
Ket [755]

The products of chemical reactions often have completely different properties than the reactants, like viscosity, boiling and melting temperatures, etc.

That is because the atoms form new and different bonds to give the products.

8 0
1 year ago
5.5x10² – 6.50x10'<br> Express the calculation in correct significant digits
OLga [1]

Answer:

6.15x10^2

Explanation:

Hello!

In this case, when performing mathematical operations with numbers in scientific notation, the first step is to write them in standard notation:

550 - 65.0

Thus, the result without any significant figures-based analysis is:

615.0

However, since 550 is significant to the ones and 65.0 to the tenths, we need to round the result to the bigger significance, in this case to the ones; therefore the appropriate result would be:

615

That in scientific notation would be:

6.15x10^2

Best regards!

5 0
3 years ago
On the atomic level energy and matter exhibit the characteristics of
shepuryov [24]

Answer:

  • <em>On the atomic level, energy and matter exhibit the characteristics of </em><u>both waves and particles.</u>

Explanation:

The dual behavior of subatomic particles as waves and particles is known as the wave - particle duality.

And this principle is the basis of the quantum theory.

Such principle is widely applied to the electrons; i.e., the electrons posses wave and particle propeties, which must be understodd as that some of their properties may be explained as if they were particles and others as if they were waves.

For example, from the particle point of view electrons have mass. You can find in internet that the mass of one electron is about 9.1093837015×10⁻³¹ kg or about 1/1836 times the mass of one proton.)

Since, the point of view of the wave characteristics, electrons have wavelength, Louis de Broglie deduced the equation that relates the wavelength and the mass, through this realtion:

  • Wavelength (λ) =  Planck’s constant (h) divided by the product of the mass (m) and the the speed (v) of the particle.

         λ = h / mv

4 0
3 years ago
Chlorine gas is added to a large flask to a pressure of 1.85 atm, at a temperature of 322 K. Phosphorus is added, and a reaction
AVprozaik [17]

Answer:

The volume of the flask is<u> 20.245 litres .</u>

Explanation:

We are given with following information-

PV=nRT -------- 1

where R =0.0821L.atom/mole.K

Molar mass of PCl_5=208.22g/mole

The given chemical equation is -

2P _(_s_)+5Cl_2 _(_g_)\rightarrow2PCl_5  _(_s_) --------- 2

Now , calculation -

Mass of PCl_5 formed = 118g

Molar mass of PCl_5 = 208.22g/mole

      Mole = \frac{mass (g)}{molar mass}

Therefore , moles of PCl_5 formed = \frac{118}{208.22}

     From equation 2 , we get to know that ,

 2mole PCl_5 formed from 5 mole Cl_2 _(_g_)

Therefore , \frac{118}{208.22} mole PCl_5 formed from \frac{5}{2} \times\frac{118}{208.22} mole Cl_2 _(_g_)

Moles of Cl_2 _(_g_) used =\frac{5\times118}{2\times208.22} mole

R= 0.0821L.atom/mole.K

Pressure (P)= 1.85atm

Temperature (T)= 322K

Moles of  Cl_2 _(_g_) (n)= \frac{5}{2} \times\frac{118}{208.22} moles

Applying  the formula above in 1 equation , that is

PV = nRT

putting the given values -

1.85 \times V=\frac{5}{2} \times\frac{118}{208.22}\times0.0821\times322

 V = 20.245 litres.

Hence , the volume of the flask is <u>20.245 litres . </u>

 

8 0
3 years ago
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