If something is going down a hill it can help slow it down
it can stop you from flying off a rollercoaster
Answer:
The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24
.
Explanation:
Velocity is a physical quantity that expresses the relationship between the space traveled by an object and the time used for it. Then, the average velocity relates the change in position to the time taken to effect that change.

Velocity considers the direction in which an object moves, so it is considered a vector magnitude.
In this case, the displacement is 192 m and the time period is 8 s. Replacing:

Solving:
velocity= 24 
<em><u>The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 </u></em>
<em><u>.</u></em>
Answer:
63.750KeV
Explanation:
We are given that
Initial velocity of second electron,
Radius,

1 m=100 cm
Magnetic field,B=0.0370 T
We have to determine the energy of the incident electron.
Mass of electron,
Charge on an electron,
Velocity,
Using the formula
Speed of electron,
Speed of second electron,

Kinetic energy of incident electron=
Kinetic energy of incident electron=
Kinetic energy of incident electron=
1KeV=1000eV
Answer:
q=3.5*10^-4
Explanation:
<u>concept:</u>
The force acting on both charges is given by the coulomb law:
F=kq1q2/r^2
the centripetal force is given by:
Fc=mv^2/r
The kinetic energy is given by:
KE=1/2mv^2
<u>The tension force:</u>
<u><em>when the plane is uncharged </em></u>
T=mv^2/r
T=2(K.E)/r
T=2(50 J)/r
T=100/r
<u><em>when the plane is charged </em></u>
T+k*|q|^2/r^2=2(K.E)charged/r
100/r+k*|q|^2/r^2=2(53.5 J)/r
q=√(2r[53.5 J-50 J]/k) √= square root on whole
q=√2(2)(53.5 J-50 J)/8.99*10^9
q=3.5*10^-4
The maximum height reached is 45.92 m