An element's atomic number is 13. How many protons would an atom of this element have?

Helppp!!!!! Please!!

neonofarm [45]

Answer:

The impulse exerted by the ball is 7.2 kg.m/s

The average force exerted on the ball by the bat is 600 N.

Explanation:

Given;

mass of the baseball, m = 0.144 kg

velocity of the baseball, v₁ = 20 m/s

velocity of the batter, v₂ = -30 m/s (opposite direction to the ball's speed)

The impulse exerted by the ball is calculated as follows;

J = ΔP = mv₁ - mv₂

ΔP = m(v₁ - v₂)

ΔP = 0.144 [20 - (-30)]

ΔP = 0.144 ( 20 + 30 )

ΔP = 0.144 (50)

ΔP = 7.2 kg.m/s

The average force exerted on the ball by the bat is calculated as;

$F = \frac{\Delta P }{t} \\\\where; t \ is \ time \ of \ contact= 0.012 \ s\\\\F = \frac{7.2}{0.012} \\\\F = 600 \ N$

3 0

3 years ago

Air is cooled in a process with constant pressure of 150 kPa. Before the process begins, air has a specific volume of 0.062 m^3/

Mama L [17]

Answer:

The pressure is constant, and it is P = 150kpa.

the specific volumes are:

initial = 0.062 m^3/kg

final = 0.027 m^3/kg.

Then, the specific work can be written as:

$W = \int\limits^{vf}_{vi} {Pdv} \, = P(vf - vi) = 150kPa*(0.0027 - 0.062)m^3/kg = -5.25 kPa*m^3/kg.$

The fact that the work is negative, means that we need to apply work to the air in order to compress it.

Now, to write it in more common units we have that:

1 kPa*m^3 = 1000J.

-5.25 kPa*m^3/kg = -5250 J/kg.

7 0

3 years ago

A proton enters a constant magnetic field of magnitude 0.050 t and traverses a semicircle of radius 1.0 mm before leaving the fi

ElenaW [278]

Velocity of proton= 4782 m/s

Explanation:

For proton, the centripetal force required for circular motion is provided by the magnetic force,

so Fm= Fc

q v B = m v²/r

m= mass of proton

v= velocity

B =magnetic field=0.05 T

q= charge= 1.6 x 10⁻¹⁹

r= radius = 1 mm =0.001 m

v= q B r/m

V= (1.6 x 10⁻¹⁹)(0.05)(0.001)/(1.673 x 10⁻²⁷)

V= 4782 m/s

4 0

4 years ago

Aisha took the train from Spokane to Seattle. The distance is 280 miles and the trip took 3.5 hours. What was the speed of the t

blsea [12.9K]

Answer:

The speed of the train is 80 miles/hour.

Explanation:

Given:

Distance from Spokane to Seattle = 280 miles

The trip from Spokane to Seattle by train took = 3.5 hours

To find the speed of the train.

Solution:

The speed is the distance per unit time. So, to find the speed of the train we will divide the total distance of the trip by the time taken to complete the trip by the train.

$Speed=\frac{Distance}{Time}$

$Speed=\frac{280\ miles}{3.5\ hours}$

$Speed=80\ miles/hour$

Thus, the speed of the train is 80 miles/hour.

4 0

3 years ago

The uncertainty in position of a proton confined to the nucleus of an atom is roughly the diameter of the nucleus. If this diame

irakobra [83]

<u>Answer:</u> The uncertainty in proton's momentum is $1.3\times 10^{-20}kg.m/s$

<u>Explanation:</u>

The equation representing Heisenberg's uncertainty principle follows:

$\Delta x.\Delta p\geq \frac{h}{2\pi}$

where,

$\Delta x$ = uncertainty in position = d = $7.8\times 10^{-15}m$

$\Delta p$ = uncertainty in momentum = ?

h = Planck's constant = $6.627\times 10^{-34}kgm^2/s^2$

Putting values in above equation, we get:

$\Delta p=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 7.8\times 10^{-15}m}\\\\\Delta p=1.3\times 10^{-20}kg.m/s$

Hence, the uncertainty in proton's momentum is $1.3\times 10^{-20}kg.m/s$

5 0

3 years ago