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fiasKO [112]
2 years ago
13

Jeff is part of a trekking team. As he climbs a hill, he drops his water bottle, which has a mass of 0.25 kilograms.

Physics
1 answer:
yulyashka [42]2 years ago
8 0

The vertical height from where Jeff dropped the bottle is 10m.

<h3>What is free falling?</h3>

When an object is released from rest in free air considering no friction, the motion is depend only on the acceleration due to gravity, g.

If we drop an object of mass m near the Earth surface from a height h, it has initial mechanical energy(P.E) of

U =mgh

When the object strikes the ground, all the potential energy converted into kinetic energy.

k.E = 1/2mv²

where v is the speed just before hitting the ground.

From energy conservation principle, initial and final mechanical energy are equal.

mgh = 1/2mv²

Given is Jeff climbs a hill. He drops his water bottle, which has a mass of 0.25 kilograms. The bottle slides down the hill and is moving at a velocity of 14 meters/second the instant it hits the ground.

The height from which bottle could fall is

h = v²/2g

Substitute the values, we get

h = (14)²/(2x9.81)

h =9.99 m

Thus,  vertical height from where Jeff dropped the bottle is approximately  10m.

Learn more about free falling.

brainly.com/question/13299152

#SPJ1

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If you wanted to know how big a tiger is, which measurements would you use?
valina [46]

Answer:

meter, kilogram

Explanation:

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The size is actually a measure of the length of the tiger, and length is measured in meters.

The mass of an object, instead, is a measure of the "amount of matter" in the substance, and it is measured in kilograms.

The other options are wrong because:

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5 0
3 years ago
Two resistors, A and B, are connected in series to a 6.0 V battery. A voltmeter connected across resistor A measures a potential
mestny [16]

Answer:

Resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

Explanation:

When the two resistors are in series, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B.

Given that V₁ + V₂ = 6.0 V and V₁ = 4.0 V,

V₂ = 6.0 V - V₁ = 6.0 V - 4.0 V = 2.0 V

Also, let the current in series be I.

So, V₁ = IR₁ and V₂ = IR₂

I = V₁/R₁ and I = V₂/R₂

equating both expressions, we have

V₁/R₁ = V₂/R₂

4.0 V/R₁ = 2.0 V/R₂

dividing through by 2.0 V, we have

2/R₁ = 1/R₂

taking the reciprocal, we have

R₂ = R₁/2

R₁ = 2R₂

From the parallel connection, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B. Since it is parallel, V₁ = V₂ = V = 6.0 V

Also, V₂ = I₂R₂ where I₂ = current in resistor B = 2.0 A and R₂ = resistance of resistor B

So, R₂ = V₂/I₂

= 6.0 V/2.0 A

= 3.0 Ω

R₁ = 2R₂

= 2(3.0 Ω)

= 6.0 Ω

So, resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

6 0
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ollegr [7]

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The moon has no atmosphere

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