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kogti [31]
3 years ago
15

How can you increase the gravitational potential energy between yourself and earth?

Physics
1 answer:
Andre45 [30]3 years ago
8 0

Answer: Use an airplane,Jet, hot air ballon etc.

Explanation:

People can fly now with the ivention of an air-object.

Thats a way to increase yourself.

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(1) A Newton is 1 kgm/s2 . Is this a fundamental unit or a derived unit?
Mrac [35]
A Newton is a derived unit.
Hope that helped:)
8 0
3 years ago
With some manipulation, the rydberg equation can be rewritten in the form e=constant×(1nf2−1ni2) which allows you to calculate t
Alinara [238K]
<span>The value of the constant needed to complete in joules to three significant figures is 2.18 x 10^-18 J.</span>
6 0
3 years ago
If the engine receives 6.45 kJ of heat energy from the reservoir at 520 K in each cycle, how many joules per cycle does it rejec
Oxana [17]

Answer:

3.72 kJ

Explanation:

QH = 6.45 kJ

TH = 520 K

Tc = 300 K

Qc = ?

By use of Carnot's theorem

Qc / QH = Tc / TH

Qc / 6.45 = 300 / 520

Qc = 3.72 kJ

6 0
3 years ago
Explain how to determine the volume of an irregularly shaped object such as a rock
alexira [117]
If you have no way to accurately measure all of the object's bumps and dimples, then the only way to measure its volume is by means of fluid displacement. 

-- Put some water into a graduated (marked) container, read the amount of water, drop the object into the container, and read the new volume in the container.  The volume of the object is the difference between the two readings.

-- Alternatively, stand an unmarked container in a large pan, and fill it to the brim. Slowly slowly lower the object into the unmarked container, while the pan catches the water that overflows from it.  When the object is completely down in the container, carefully remove the container from the pan, and measure the volume of the water in the pan.  It's equal to the volume of the object.
6 0
3 years ago
A certain digital camera having a lens with focal length 7.50 cmcm focuses on an object 1.70 mm tall that is 4.70 mm from the le
Crank

Answer:

a. 7.62cm

b. Real and inverted

c. 2.76 cm

d. 3450

Explanation:

We proceed as follows;

a. the lens equation that relates the object distance to the image distance with the focal length is given as follows;

1/f = 1/p + 1/q

making q the subject of the formula;

q = pf/p-f

From the question;

p = 4.70m

f = 7.5cm = 0.075m

Substituting these, we have ;

q = (4.7)(0.075)/(4.7-0.075) = 0.3525/4.625 = 0.0762 = 7.62 cm

b. The image is real and inverted since the image distance is positive

c. We want to calculate how tall the image is

Mathematically;

h1 = (q/p)h0

h1 = (7.62/4.70)* 1.7

h1 = 2.76 cm

d. We want to calculate the number of pixels that fit into this image

Mathematically:

n = h1/8 micro meter

n = 2.76cm/8 micro meter = 2.76 * 10^-2/8 * 10^-6 = 3450

3 0
3 years ago
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