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GarryVolchara [31]

3 years ago

13

A student is working hard on a chemistry lab experiment that uses a strong acid. Halfway through the lab, the student gets hungr

y and starts eating a bag of chips. When the student licks their fingers, they start to have a severe reaction. summary

1 answer:

Hitman42 [59]3 years ago

7 0

A student consumed dangerous chemicals

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mr_godi [17]

Answer:

A

B that is Cr,MN,Fe,Co. is the correct answer

C

D

4 0

1 year ago

The flask contains 10.0mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.320 M NaOH. What is the init

yan [13]

This question is incomplete, the complete question is;

The flask contains 10.0mL of HCl and a few drops of phenolphthalein indicator.

The buret contains 0.320 M NaOH,

It requires 11.2 mL of the NaOH solution to reach the end point of the titration

What is the initial concentration of HCI?

Answer:

initial concentration of HCl is 0.3584 M

Explanation:

Given that;

the reaction between HCl and NaOH is 1:1 molar

HCl(aq) + NaOH(aq) -------> NaCl(aq) + H2O(l)

we know that molarity is the number of moles of solute per liter of solution

so moles of NaOH consumed

= ( 0.320 mol / 1000ml) × 11.2ml

= 0.003584 mol

now

0.003584 moles of NaOH reacts with 0.003584 moles of HCl

moles of HCl present in the 10.0ml solution = 0.003584 mol

therefore the initial concentration of HCl

= ( 0.003584 mol / 10.0ml )× 1000ml

= 0.3584 M

the initial concentration of HCl is 0.3584 M

5 0

3 years ago

Aluminum oxide was prepared by heating 225 g of chromium (III) oxide with 125 g of aluminum. Calculate the percent yield of 100.

Veronika [31]

Answer:

66.25%

Explanation:

4 0

4 years ago

Draw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without re-arrang

sergij07 [2.7K]

Answer:

See explanation

Explanation:

Hydration of alkenes is a common reaction in organic chemistry. Hydration is simply the addition of water to an alkene. This is an acid catalysed reaction as we can see from the mechanism attached.

Recall that our task is to carry out the synthesis of 2-butanol using an alkene starting material in which there will be no rearrangement of the intermediate carbocation. If we start with the compound shown in the image (but-2-ene), the first step is the formation of the secondary carbocation. This is followed by the addition of water. Subsequently, the added water is deprotonated by another water molecule to yield 2-butanol and the acid catalyst. All these steps have been clearly outlined in the image attached.

5 0

4 years ago

How much Pb(NO3)2 would need to be added to 100 mL of water to make a saturated solution at 40°C.

gtnhenbr [62]

Answer:

70g of Pb(NO3)2 would need to be added

Explanation:

As you can see in the solubility graph of lead nitrate, Pb(NO₃)₂, the solubility of this salt (That is, the maximum amount of the salt that can be dissolved in 100g of the solvent producing a homogeneous solution) is 70g in 100g of water = 70g of the salt in 100mL of water.

A saturated solution is also defined as solubility: The maximum amount of a solute that can be dissolved in a solvent.

That means:

70g of Pb(NO3)2 would need to be added

4 0

3 years ago