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3 years ago

What prevents most small meteoroids from hitting earth surface?

1 answer:

4 0

Gravity is the solution!. We are lucky to have Jupiter in our solar system. Jupiter's gravity is strong enough to pull meteorites towards itself.

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Water can be formed in the following reaction:

just olya [345]

Answer

Explanation

We have a balanced chemical equation from the question that depicts the formation of water.

2H2+O2-->2H2O,

We can clearly see from the equation that, the formation of 2 moles of water molecules requires the input of 2 moles of hydrogen and 1 mole of Oxygen.

So indirectly, it tells that the moles of water molecules will be double of the moles of Oxygen molecules used in the reaction.

So if we say that 6 moles of oxygen is used and the reaction is going in such a way that hydrogen is not a limiting reactant, then 12 moles of water will be produced.

Hope it help!

8 0

3 years ago

Green plants use light from the Sun to drive photosynthesis, a chemical reaction in which liquid water and carbon dioxide gas fo

Luda [366]

Answer:

0.800 mol of O2

Explanation:

<em>Calculate the moles of oxygen produced by the reaction of 0.800mol of carbon dioxide.</em>

The balanced equation for the reaction is given as;

6CO2 + 6H2O → C6H12O6 + 6O2

From the reaction;

6 mol of CO2 produces 6 mol of O2

0.0800 mol of CO2 would produce x mol of O2

6 = 6

0.0800 = x

Solving for x;

x = 6 * 0.800 / 6

x = 0.800 mol

5 0

2 years ago

Carbon reacts with steam (h2o) at high temperatures to produce hydrogen and carbon monoxide. if 2 mol of carbon are exposed to 3

Ne4ueva [31]

The balanced equation for the above reaction is as follows;
C + H₂O ---> H₂ + CO
stoichiometry of C to H₂O is 1:1
1 mol of C reacts with 1 mol of H₂O
we need to find which is the limiting reactant
2 mol of C and 3.1 mol of H₂O
therefore C is the limiting reactant and H₂O is in excess.
stoichiometry of C to H₂ is 1:1
then number of H₂ moles formed are equal to C moles reacted
number of H₂ moles formed = 2 mol

4 0

3 years ago

The change in entropy is related to the change in the number of moles of gas molecules. Determine the change in moles of gas for

tester [92]

The given question is incomplete. The complete question is:

The change in entropy is related to the change in the number of moles of gas molecules. Determine the change in moles of gas for each of the reactions and decide if the entropy increases decreases or has little to no change:

A. $K(s)+O_2(g)\rightarrow KO_2(s)$

B. $CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)$

C. $CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)$

D. $N_2O_2(g)\rightarrow 2NO(g)+O_2(g)$

Answer: A. $K(s)+O_2(g)\rightarrow KO_2(s)$ : decreases

B. $CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2(g)$ : decreases

C. $CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)$ : no change

D. $N_2O_2(g)\rightarrow 2NO(g)+O_2(g)$ : increases

Explanation:

Entropy is defined as the randomness of the system.

Entropy is said to increase when the randomness of the system increase, is said to decrease when the randomness of the system decrease and is said to have no change when the randomness remains same.

In reaction $K(s)+O_2(g)\rightarrow KO_2(s)$ , as gaseous reactant is changed to solid product, entropy decreases.

In reaction $CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)$ , as 4 moles of gaseous reactants is changed to 2 moles of gaseous product, entropy decreases.

In reaction $CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)$ , as 3 moles of gaseous reactants is changed to 3 moles of gaseous product, entropy has no change.

In reaction $N_2O_2(g)\rightarrow 2NO(g)+O_2(g)$ , as 1 mole of gaseous reactant is changed to 3 moles of gaseous product, entropy increases.

7 0

3 years ago

How much heat is evolved when 22.5 grams of a food sample changes the temperature of 0.42 kg of water by 4.4 degree C. Assume sp

irakobra [83]

The answer is C. Assume specific heat to be 4.18 J/g/C

3 0

3 years ago