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zimovet [89]
3 years ago
5

Select all that are true

Chemistry
1 answer:
kipiarov [429]3 years ago
8 0
I think it’s B not quite sure ! Sorry
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How is atomic number different from mass number?
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Well, as you can clearly see 

<span>The atomic number of an element is basically the number of protons it has. So yes, for every element this is different. Now, the mass number of an element as known, is the number of protons+the number of neutrons.  So theoretically as we can see, this number should be a whole number, but since there are different isotopes (atoms of the same element with different numbers of neutrons) of each element, most periodic tables take account of that, so they often include decimals as seen. 

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An asteroid hit the Yucatán Peninsula about 65 million years ago,
Morgarella [4.7K]

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C. It blocked out sunlight

Explanation:

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Rina8888 [55]
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The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute th
MrRissso [65]

The question is incomplete, complete question is :

The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute the ratio of the reaction rate constants for these two reactions at 25°C.

\frac{K_1}{K_2}=?

Activation energy of the reaction 1 ,Ea_1 = 14.0 kJ/mol

Activation energy of the reaction 2,Ea_1  = 11.9 kJ/mol

Answer:

0.4284 is the ratio of the rate constants.

Explanation:

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

The expression used with catalyst and without catalyst is,

\frac{K_2}{K_1}=\frac{A\times e^{\frac{-Ea_2}{RT}}}{A\times e^{\frac{-Ea_1}{RT}}}

\frac{K_2}{K_1}=e^{\frac{Ea_1-Ea_2}{RT}}

where,

K_2 = rate constant reaction -1

K_1 = rate constant reaction -2

Activation energy of the reaction 1 ,Ea_1 = 14.0 kJ/mol = 14,000 J

Activation energy of the reaction 2,Ea_1  = 11.9 kJ/mol = 11,900 J

R = gas constant = 8.314 J/ mol K

T = temperature = 25^oC=273+25=298 K

Now put all the given values in this formula, we get

\frac{K_1}{K_2}=e^{\frac{11,900- 14,000Jl}{8.314 J/mol K\times 298 K}}=2.3340

0.4284 is the ratio of the rate constants.

7 0
3 years ago
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