Does Charles’s law hold when the gas becomes a liquid?

Which force is most responsible for slowing a bicycle down when the brakes are applied

Leya [2.2K]

Friction is most responsible for slowing a bicycle down when the brakes are applied

7 0

3 years ago

How many valence electrons would an element with atomic number 113 have?

marshall27 [118]

How does the law of conservation of mass apply to this reaction: C2H4 + O2 → H2O + CO2?

4 0

3 years ago

Measurements show that unknown compound X has the following composition: element mass % carbon 41.0% hydrogen 4.58% oxygen 54.6%

anastassius [24]

Answer:

CHO

Explanation:

Carbon = 41%, Hydrogen = 4.58%, oxygen = 54.6%

Step 1:

Divide through by their respective relative atomic masses

41/ 12, 4.58/1, 54.6/16

3.41 4.58 3.41

Step 2:

Divide by the lowest ratio:

3.41/3.41, 4.58/3.41, 3.41/3.41

1, 1, 1

Hence the empirical formula is CHO

8 0

3 years ago

Based on the sign of E cell, classify these reactions as spontaneous or non spontaneous as written.? assume standard conditions.

sammy [17]

A electrochemical reaction is said to be spontaneous, if $E^{0} cell is positive.$

Answer 1:
Consider reaction: Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s)

The cell representation of above reaction is given by;
 $S^{2-}/S // Ni^{2+}/Ni$

Hence, $E^{0}cell = E^{0} Ni^{2+/Ni} - E^{0} S/S^{2-}$
we know that, ${E^{0} Ni^{2+}/Ni = -0.25 v$
and ${E^{0} S/ S^{2-} = -0.47 v$

Therefore, $E^{0} cell$ = - 0.25 - (-0.47) = 0.22 v

Since, $E^{0} cell$ is positive, hence cell reaction is spontaneous
.....................................................................................................................

Answer 2:
Consider reaction: Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)

The cell representation of above reaction is given by;
 $H_{2} / H^{+} // Pb^{2+} /Pb$

Hence, $E^{0}cell = E^{0} Pb/Pb^{2+} - E^{0} H_{2}/H^{+}$
we know that, ${E^{0} Pb^{2+}/Pb = -0.126 v$
and ${E^{0} H_{2}/ H^{+} = -0 v$

Therefore, $E^{0} cell$ = - 0.126 - 0 = -0.126 v

Since, $E^{0} cell$ is negative, hence cell reaction is non-spontaneous.

....................................................................................................................

Answer 3:
Consider reaction: 2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)

The cell representation of above reaction is given by;
 $Cr/Cr^{2+} // Ag^{+}/Ag$

Hence, $E^{0}cell = E^{0} Ag^{+}/Ag - E^{0} Cr/Cr^{2+}$
we know that, ${E^{0} Ag^{+}/Ag = -0.22 v$
and ${E^{0} Cr/ Cr^{2+} = -0.913 v$

Therefore, $E^{0} cell$ = - 0.22 - (-0.913) = 0.693 v

Since, $E^{0} cell$ is positive, hence cell reaction is spontaneous

8 0

4 years ago

Read 2 more answers

Strengths as bases: H2O, F-, Cl-, NO,, and CN-

navik [9.2K]

Answer:

Cl^-<NO3^-<H2O<F^-<CN^-

Explanation:

When we talk about base strength we are referring to how easily a chemical specie accepts protons.

The greater the ability of a specie to accept H^+, the greater its base strength.

The order of increasing base strengths of the species listed are shown in the answer above.

3 0

3 years ago